A person eating at a cafeteria must choose 4 of the 13 vegetables on offer. calculate the number of elements in the sample space for this experiment.
Answer: The number of elements in the sample space for this experiment can be found using the combination formula because the order does not matter here.
Therefore, the number of elements in the sample space for this experiment is:
Therefore, the number of elements in the sample space for this experiment is 715.
1935 rounded to the nearest thousand = 2000....because it is closer to 2000 then to 1000.
<u>Answer-</u>
<em>The length of line segment WU is</em><em> 4 cm</em><em>.</em>
Option 1. 4 cm is correct.
<u>Solution-</u>
As given that, RSTU is an parallelogram.
RT and SU are its two diagonals. They intersect each other at point W.
Properties of parallelogram is that they bisect each other.
i.e SW = WU and RW = WT
As given that, SW = 4 cm.
So, WU = SW = 4 cm
Therefore, the length of line segment WU is 4 cm.
9514 1404 393
Answer:
(x, y) ≈ (1.1642, 3.3930) and (3.4358, -0.39297)
Step-by-step explanation:
Solve the first equation for y, then substitute into the second.
5x +4/y = 7
4/y = 7 -5x
4/(7 -5x) = y
Then the second equation becomes ...
4x +x/(4/(7 -5x)) = 5
4x +x(7 -5x)/4 = 5
16x +7x -5x^2 = 20 . . . . . multiply by 4
5x^2 -23x +20 = 0 . . . . . put in standard form
We can use the quadratic formula to solve this.
x = (23±√((-23)² -4(5)(20)))/(2(5)) = (23±√129)/10
x = 2.3 ±√1.29 ≈ {1.1642, 3.4358}
y = 4/(7 -5x) = {3.3930, -0.39297}
Solutions are (x, y) ≈ (1.1642, 3.3930) and (3.4358, -0.39297).
1) C 392 in2
2) 125cm³
3) D 64 in3
