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Amanda [17]
3 years ago
6

The number of subscribers y to a newspaper after t years is shown by the equation below: y = 75(0.95)t Which conclusion is corre

ct about the number of subscribers to the newspaper? It increased by 75% every year. It decreased by 75% every year. It increased by 5% every year. It decreased by 5% every year.
Mathematics
2 answers:
kodGreya [7K]3 years ago
5 0

Answer:

  It decreased by 5% every year

Step-by-step explanation:

When t increases by 1, the number of subscribers is multiplied by another factor of 0.95, making the new value 5% less than the previous one.

The number of subscribers decreased by 5% every year.

BartSMP [9]3 years ago
3 0

Answer:

It decreased by 5% every year.

Step-by-step explanation:

Given : The number of subscribers y to a newspaper after t years is shown by the equation below: y = 75(0.95)^t

To Find: Which conclusion is correct about the number of subscribers to the newspaper?

Solution:

y = 75(0.95)^t

Initial amount of subscribers = 75

We can rewrite the given equation as y = 75(1-0.05)^t  ---A

General exponential decay function  : y=a(1-r)^t    --B

where y is the amount after t years

a is the initial amount

r is the rate of decrease in decimals

t is the time

If we compare A with B

So, rate of decrement = 0.05=5%

So, This shows that the number of subscribers decreased by 5% every year.

Hence Option D is correct.

It decreased by 5% every year.

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what is the least whole number that has the remainders 10,12, and 15 when divided by 16, 18. and 21, respectively
AnnZ [28]

Answer:

1002

Step-by-step explanation:

First find difference between the divisors and remainders.

16-10=6\\18-12=6\\21-15=6

Here, the difference between the divisors and remainders is equal.

So, the required number is equal to LCM of (16,18,21)-6

16=2^4\\18=2(3^2)\\21=3(7)

LCM of (16,18,21)=2^4(3^2)(7)=1008

Required Number =1008-6=1002

7 0
3 years ago
How do I do this? Please explain in detail.
umka2103 [35]
22.5/(x-6) + 22.5/(x+6) = 9
multiply by x-6
=> (x-6)22.5/(x-6) + (x-6)22.5/(x+6) = 9(x-6)
=> 22.5 + (x-6)22.5/(x+6) = 9(x-6)
multiply by x+6
=> (x+6)22.5 + (x+6)(x-6)22.5/(x+6) = 9(x-6)(x+6)
=> (x+6)22.5 + (x-6)22.5 = 9(x-6)(x+6)
distribute
=> 22.5x+6(22.5) + 22.5x - 6(22.5) = 9(x^2 - 36)
=> 45x = 9x^2 - 9(36)
=> 0 = 9x^2 - 45x - 9(36)
divide by 9
=> 0 = x^2 - 5x - 36
=> 0 = x^2 - 5x - 36
=> 0 = (x - 9)(x + 4)
x=9 and -4
8 0
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