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3 years ago

SOMEONE PLEASE HELP MEE

Mathematics

1 answer:

melomori [17]3 years ago

6 0

Answer:

The missing numbers are 12 and 39 respectively

Step-by-step explanation:

From the table, we can see that the ratio of the left column to the right is 3/5

So at any point in time, the values on a particular row of the table must conform

to this ratio

In other light, we have to multiply what we have on the left by 5/3 to get what’s on the right

and we have to multiply what we have on the right by 3/5 to get what’s on the left

We have this as follows;

20 * 3/5 = 12

and;

65 * 3/5 = 39

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Find the equation of the line parallel to the graph of 7x-3y=21 that has an x-intercept of -1.

zhuklara [117]

To start this, you would have to get y by itself to have an equation you can graph. Start by subtracting 7x from both sides.
-3y= -7x+21
Next, divide both sides by -3
y = 7/3x + 7
A parallel line would have the same slope of 7/3x. Since you need to have an intercept of -1 the equation would be y = 7/3x -1

8 0

4 years ago

If the commuter wants to buy 20 weeks of tickets, how much must he add to his account?

pentagon [3]

Answer:

$55

Step-by-step explanation:

Start with $245.

Calculate to total money the commuter needs to buys 20 weeks of tickets.

Multiply the number of weeks by the price per week.

20 X $15 = $300

He will need $300 for 20 weeks of tickets.

Subtract what he has from the amount he needs.

$300 - $245 = $55

Therefore the commuter will need to add $55 to the account to afford tickets for 20 weeks.

7 0

3 years ago

Please help will mark brainliest

Butoxors [25]

4, 16
-1, 1
3, 9
12, 144
16, 256

The rule is y=x^2. If you square all the numbers on the x side, you will get the numbers on the y side. 4 times 4 = 16. -1 times -1 =1. 3 times 3 =9, and so on.

5 0

3 years ago

(04.05 LC)

Komok [63]

correct answer is option d.

Step-by-step explanation:

Here, we have The following expression to check Which of the following is a polynomial with roots: −square root of 3 , square root of 3, and 2 :

a. x3 + 3x2 − 5x − 15

For $-\sqrt{3}$ , $x^{3} + 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3} + 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!

b. x3 + 2x2 − 3x − 6

For $-\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(-\sqrt{3}) ^{3} + 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) -6$ = 0 .

For $\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(\sqrt{3}) ^{3} + 2(\sqrt{3} )^{2} -3(\sqrt{3} ) -6$ = 0.

For 2 , $x^{3} + 2x^{2} -3x -6$ ⇒ $(2) ^{3} + 2(2)^{2} -3(2 ) -6$ $\neq 0$ . So, this isn't the one. We move on further!

c. x3 − 3x2 − 5x + 15

For $-\sqrt{3}$ , $x^{3}- 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3}- 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!