Let the amount deposited (principal) be x, then the amount after the required time = 2x.
A = P(1 + r/n)^nt: where A is the future value = 2x, P is the principal = x, r is the rate = 0.75%, n is the number of accumulation in a year = 12, t is the number of years.
2x = x(1 + 0.0075/12)^12t
2 = (1 + 0.000625)^12t
log 2 = 12t log (1.000625)
log 2 / log (1.000625) = 12t
1109.38 = 12t
t = 92 years
Answer:
= 2 × 625 – 5 × 125 + 25 + 3 × 5 + 2
=1250 – 625 + 25 + 15 +2
= 1292 – 625
= 667
Answer:
(-2, ∞)
Step-by-step explanation:
A function is "increasing" when its graph goes up to the right, the slope is positive. At a turning point (maximum or minimum), the function is neither increasing nor decreasing.
<h3>Increasing interval</h3>
The graph has a minimum at x = -2. To the left of that point, the graph goes up to the left, which is the same as down to the right (decreasing).
To the right of x = -2, the graph goes up to the right (increasing). It continues to increase for all values of x > 2. The interval where the function is increasing is said to be ...
-2 < x < ∞
The lack of "or equal to" tells you the interval is "open" and is delimited by parentheses in interval notation:
increasing; (-2, ∞)
Determine the slope and y-intercept from the following equation: 4x + y = -10
Question 9 options:
slope: 4 y-intercept: (0,10)
slope: -4 y-intercept: (0,10)
slope: -4 y-intercept: (0,-10)
slope: 4 y-interce
