First step: Find out the prime numbers that make up the radical, for example, 120 would be 2x2x2x5x3
Second step: If there is 2 of the same number that repeats just put that number in the front of the resulting radical
Third: Just multiply the remaining radicals together and put the number in front of it.
Now you have
Answer: see proof below
<u>Step-by-step explanation:</u>
Since (a, b) is equidistant from (-a, 2) and (2, -b), then it is the midpoint of the those two points. Use Midpoint formula to find (a, b).

3(a + b) - 4 = 0

<em>Notice that I changed the equation to "negative 4" because the equation you provided did not make a true statement.</em>
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