Question

Write a C++ program to count even and odd numbers in array. The array size is 50. The array elements will be entered by the user.

Answer 1

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int numbers[50];

   int evekount = 0, odkount = 0;

   for(int i = 0; i<50;i++){

       cin>>numbers[i];

       if(numbers[i]%2==0){            evekount++;        }

       else{            odkount++;        }

   }

   cout<<"Even Count: "<<evekount<<endl;

   cout<<"Odd Count: "<<odkount<<endl;

   return 0;

}

Explanation:

This declares the integer array of number

   int numbers[50];

This initializes the even count and odd count to 0

   int evekount = 0, odkount = 0;

This iterates from 1 to 50

   for(int i = 0; i<50;i++){

This gets input for the array

       cin>>numbers[i];

This checks for even

       if(numbers[i]%2==0){            evekount++;        }

This checks for odd

       else{            odkount++;        }

   }

This prints the even count

   cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

   cout<<"Odd Count: "<<odkount<<endl;