The second quartile is also the median. which is 50% of the data. So 1/2 of the data lies below it, and 1/2 of the data lies above it.
the correct answer would be A. the data value of 2.5 will lie below the second quartile.
2/4= 10/20
1 4/10=14/10 14/10=28/20
10/20×28/20=7/10
I hope this helped!!!:)
Answer:
0.918 is the probability that the sample average sediment density is at most 3.00
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 2.80
Standard Deviation, σ = 0.85
Sample size,n = 35
We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling:

P(sample average sediment density is at most 3.00)
Calculation the value from standard normal z table, we have,
0.918 is the probability that the sample average sediment density is at most 3.00
11:02
i don't know if im correct, sorry.
(x^1/2 y^-2/3)^-6
= x^(1/2*-6) y^[(-2/3) *(-6)]
= x^-3 y ^4
= y^4 / x^3
answer is D. y^4 / x^3