1-2:<span>Yes. But not all parallelograms are squares</span><span>
3-false ! are </span><span>plane figures.
4-True ! </span>Every square is a rhombus<span>
5-False , </span><span>every rhombus is not a square.
6-7 : </span>Yes, all Squares are rectangles, but not all rectangles are squares because it needs to have all equal sides.
Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:

Are you looking for where they cross ? if so its (-1,2)
The first option 12a - 20