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Aleks04 [339]
3 years ago
11

Find the surface area of the triangular prism shown below. 64557

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:you just have to mutlkplaye 5 and 12 like what’s nine plus ten 21

Step-by-step explanation:

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after spending 1/3 of her money on a TV and 1/4 of it on a game console,Cindy still had $600 left. how much money did she spend
dmitriy555 [2]

Answer:


$360 on game console

$480 on tv

$1440 before spending money

x - 1/3x - 1/4x = $600

12/12x - 4/12x - 3/12x = $600

5/12x = $600

x = (12/5)($600)

x = $1440

Game Console = (1/4)(1440) = $360


Hope this helped!

6 0
3 years ago
Which is greater 4.221 or 4.022
Ahat [919]
4.221 is greater because of the .221
                                                  .022  see
8 0
4 years ago
A particle is moving with the given data. Find the position of the particle. a(t) = t2 − 2t + 9, s(0) = 0, s(1) = 20
lozanna [386]

Answer:

Position of the particle is 20.

Step-by-step explanation:

Position function is integration of velocity function.

Velocity function is integration of acceleration function.

So, let's integrate the given a(t) to get v(t)

If we integrate v(t) then we get s(t)

It is given the values of s(0) =0 and s(1)=20

So, position of the particle is difference of 20, 0. That's 20-0 =20.

6 0
3 years ago
Calculate the area of the shaded region.
Nostrana [21]

Let A be the area of the sector in the larger circle (radius 12 cm) whose central angle is subtended by the labeled arc with measure 45 deg, and let a be the area of the sector in the smaller circle (radius 8 cm) with the same central angle. The area you want is A-a.

We have

\dfrac A{\pi(12\,\mathrm{cm})^2}=\dfrac{45^\circ}{360^\circ}\implies A=18\pi\,\mathrm{cm}^2

\dfrac a{\pi(8\,\mathrm{cm})^2}=\dfrac{45^\circ}{360^\circ}\implies a=8\pi\,\mathrm{cm}^2

So the area of the shaded region is 18\pi-8\pi=10\pi.

7 0
3 years ago
Quadrilateral PQRS is transformed by translating it 6 units to the right and then rotating it 90° clockwise
Elina [12.6K]

Answer:

(y, -x -6)

Step-by-step explanation:

<em>The coordinates of PQRS is not given, however we'll assume the coordinates of PQRS to be (x,y)</em>

<em />

The first transformation: 6 units right

(x,y) -> (x + b, y)

Where b = 6

So, the new coordinates will be

(x + 6, y)

The second transformation: 90° clockwise

(x,y) -> (y,-x)

So, the new coordinates will be

(x + 6, y)-> (y, -x -6)

<em>Hence, the new coordinates of PQRS is (y, -x - 6)</em>

7 0
3 years ago
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