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Semmy [17]
3 years ago
8

Evaluate each expression. HELP!!!!!!!!!!!!!

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

Step-by-step explanation:

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Write an equation to represent the N'th term of the sequence (2,-1.-4,-7,...)
mr_godi [17]

Answer: a(n) = 5 - 3n

the sequence has:

a1 = 2

a2 = -1

a3 = -7

.........

we can see that: a2 - a1 = a3 - a2 = -3

=> the sequence is a  arithmetic sequence

=> the distance between the numbers is d = -3

because this sequence is a  arithmetic sequence

=> a(n) = a1 + (n - 1)d = 2 + (n - 1).(-3) = 5 - 3n

Step-by-step explanation:

7 0
3 years ago
What is the average rate of change for the function f(x)=3x^2 -5 on the interval −3 ≤ x ≤ −1 ?
Anestetic [448]

Answer:

-12

Step-by-step explanation:

Let b = -1 and a = -3

The average rate of change = \frac{f(b) - f(a)}{b - a}

f(b) = f(-1) = 3(-1)^2 - 5 = 3 - 5 = -2

f(a) = f(-3) = 3(-3)^2 - 5 =27 - 5 = 22

f(b) - f(a) = -2 - 22 = -24

b - a = -1 + 3 = 2

\frac{f(b) - f(a)}{b - a} = -24/2 = -12

4 0
3 years ago
Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
I need help please help me
andreev551 [17]

Answer:

The answer is B :))

Step-by-step explanation:

Brainliest?

5 0
3 years ago
What is the equation of the linear function?
docker41 [41]

Answer:

y = mx+b

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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