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Vlad1618 [11]
3 years ago
14

Need answers ASAP please

Mathematics
1 answer:
Zanzabum3 years ago
4 0

Answer:

angle classification is <u>acute</u>

side classification is <u>equilateral</u>

Step-by-step explanation:

You might be interested in
What is the value of x?<br> Enter your answer in the box.<br> x =
Svetllana [295]

Answer:

Step-by-step explanation:

The two triangles are similar and therefore we can set up a proportion

9/(9 + 72) = (3x - 20)/(3x - 20 + 56)       Combine like terms on the right

9/(81) = (3x - 20)/(3x + 36)                      Cross multiply

9(3x + 36) = 81 (3x - 20)                         Remove the brackets.

27x + 324 +1620 = 243x                        Add 1620 to both sides

27x + 324 + 1620 = 243x                       Subtract 27x from both

1944 = 216x                                            divide both sides by 216

x = 9                                  

If you feel comfortable canceling the size of the numbers can be reduced.

9/81 = 1/9

1/9 = (3x - 20)/(3x + 36)

3x + 36 = 9(3x - 20)

3x + 36 = 27x - 180

36 + 180 = 24x

216 = 24x

216/24 = x

x = 9

There is another cancelation possible, but this is simple enough.

6 0
3 years ago
Circle O has a center at (-2, 10) and a
allsm [11]

Answer:

B

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

distance =  \sqrt{(y1 - y2)^{2} +  {(x1 - x2)}^{2}  }

A. Distance between 2 points

=  \sqrt{ {(10 + 5)}^{2}  + ( - 2 + 6)^{2} }  \\  =  \sqrt{15 ^{2} +  {4}^{2}}  \\  =  \sqrt{241}  \\  = 15.524 \: units

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

=  \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2}  }  \\  =  \sqrt{ {6}^{2} }  \\  = 6 \: units

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

=  \sqrt{ {(10 - 4)}^{2}  +  {( - 2 - 6)}^{2} }  \\  =  \sqrt{ {6}^{2}  + ( - 8)^{2} }  \\  =  \sqrt{100}  \\  = 10 \: units

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

=  \sqrt{ {(10 - 8)}^{2}  +  {( - 2 - 8)}^{2} }  \\  =  \sqrt{2^{2}  + ( - 10)^{2} }  \\  =  \sqrt{104}  \\  = 10.198 \: units

(to 5 s.f.)

Point D also lies outside Circle O.

8 0
4 years ago
PLEASE HELP QUICK!!!!!
astra-53 [7]

Answer:

8

Step-by-step explanation:

check this out!

-5(a+3)=- 55

-5a-15=- 55

-5a= -55+15

-5a= -40

-5a/-5 =-40/-5

a=8

4 0
4 years ago
Read 2 more answers
"According to this diagram what is sin 23"?
AlekseyPX
Sinx is the opposite side over the hypotenuse. The opposite side depicted here is 5, while the hypotenuse is 13.
Therefore, the answer is 5/13, or B.
6 0
3 years ago
Read 2 more answers
Pls answer all the questions​
Bas_tet [7]

Answer:

A) 108 degrees

B) 90 degrees

C) 270 degrees

5 0
3 years ago
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