Answer:
Its B
Step-by-step explanation:
I remember doing this :)
Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
Answer:
78.5°
Step-by-step explanation:
We solve for the above question, using the formula for the Trigonometric function of Cosine
cos θ = Adjacent/Hypotenuse
Adjacent = The distance between the house and the base of the ladder = 4 feet
Hypotenuse = Length of the Ladder = 20 feet
Hence,
cos θ = 4/20
θ = arc cos(4/20)
θ = 78.463040967°
Approximately = 78.5°
Therefore, the angle that the ladder makes with the ground is 78.5°
Answer:
x=8
Step-by-step explanation:
5.8+5.9x=6x+5
5.9x-6x=5-5.8
-0.1x= -0.8
x=8
