Answer:
((1+2)*3+4)*5
Step-by-step explanation:
1+2×3+4×5=65
-----------------------
- ((1+2)×3+4)×5=
- (3×3 + 4)×5 =
- (9 + 4)×5 =
- 13×5 = 65
Answer:
L=8
Step-by-step explanation:
S=smaller number
L=larger number
S+L=5 : S=5-L
L=14+2S
substitute for S:
L=14+2(5-L)
solve for L:
L=14+10-2L
3L=24
L=8
5/54 or approximately 0.092592593
There are 6^3 = 216 possible outcomes of rolling these 3 dice. Let's count the number of possible rolls that meet the criteria b < y < r, manually.
r = 1 or 2 is obviously impossible. So let's look at r = 3 through 6.
r = 3, y = 2, b = 1 is the only possibility for r=3. So n = 1
r = 4, y = 3, b = {1,2}, so n = 1 + 2 = 3
r = 4, y = 2, b = 1, so n = 3 + 1 = 4
r = 5, y = 4, b = {1,2,3}, so n = 4 + 3 = 7
r = 5, y = 3, b = {1,2}, so n = 7 + 2 = 9
r = 5, y = 2, b = 1, so n = 9 + 1 = 10
And I see a pattern, for the most restrictive r, there is 1 possibility. For the next most restrictive, there's 2+1 = 3 possibilities. Then the next one is 3+2+1
= 6 possibilities. So for r = 6, there should be 4+3+2+1 = 10 possibilities.
Let's see
r = 6, y = 5, b = {4,3,2,1}, so n = 10 + 4 = 14
r = 6, y = 4, b = {3,2,1}, so n = 14 + 3 = 17
r = 6, y = 3, b = {2,1}, so n = 17 + 2 = 19
r = 6, y = 2, b = 1, so n = 19 + 1 = 20
And the pattern holds. So there are 20 possible rolls that meet the desired criteria out of 216 possible rolls. So 20/216 = 5/54.
It's sometimes true.
One example is the least common multiple of 2 and 3 is 6, which is their product.
But the product isn't always the answer because (example 2:) the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.
Ergo, it is only sometimes true.
N(2x+y) = x +1
Differentiate both sides, using the Chain Rule on the left side.
(1 / (2x + y)) * d(2x + y)/dx = 1
(1 / (2x + y)) * (2 + dy/dx) = 1
<span>Rearrange to isolate dy/dx.
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