All categories

3 years ago

Thanks for the help thanks again

Mathematics

2 answers:

liberstina [14]3 years ago

8 0

Answer:

ur welcome

Step-by-step explanation:

- spongebob

Rasek [7]3 years ago

4 0

Answer:

Your Welcome

Step-by-step explanation:

No Problem

You might be interested in

What is the exact value of cos 30° ? Enter your answer, as a simplified fraction, in the box.

dezoksy [38]

I think this is the answer cos 30=3–√2

8 0

3 years ago

Read 2 more answers

******PLEASE HURRY!!!!! WILL GIVE BRAINLIEST ****************

Eduardwww [97]

2 number are x and y
X=10,y=65

8 0

3 years ago

Single digits numbers of 420

yaroslaw [1]

The singles digit is 0.

The 2 is the tens digit and the 4 is the hundreds digit.

6 0

3 years ago

Simplify the following question

fiasKO [112]

Answer:

− 2sin(b) / cos(2b)

Step-by-step explanation:

DIFFERENTIATE W.R.T. B is a different method entirely

We simply add together the numerators and set with 2cos

then keep this number and add to sinb and square it.

then repeat initial 2 + cosb ^2 but instead of multiplying its add.

Then set the whole division to -sin (2b) squared then +1

 − 2cos(b)(3(sin(b))^2+(cos(b))^2) / −(sin(2b)) ^2 +1 

5 0

2 years ago

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago