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8090 [49]
3 years ago
10

How do I solve this problem: 6c - 8 - 2c = -16

Mathematics
2 answers:
ale4655 [162]3 years ago
7 0

Answer:

c = -2

Step-by-step explanation:

6c-8-2c = -16

4c -8 =-16

4c = -16 +8

4c = -8

4c/4 = -8/4

c = -2

Answred by Gauthmath

sineoko [7]3 years ago
6 0

Step-by-step explanation:

6c-8-2c=-16

6c-8+8-2c=-16+8

6c-2c=24

4c=-8

4c/4=-8/4

c=-2

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3 years ago
Will give brainliest, please help fast​
Gekata [30.6K]

Answer:

Converting the equation x^2-20x+13=0 into completing the square method we get: \mathbf{(x-10)^2=87}

Step-by-step explanation:

we are given quadratic equation: x^2-20x+13=0

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Looking at the given equation x^2-20x+13=0

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So, we need to add and subtract (10)^2 on both sides

x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87

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