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3 years ago

Please help me find the area

Mathematics

1 answer:

laiz [17]3 years ago

3 0

Answer:

594

Step-by-step explanation:

To find the area of a rectangle it is length * width

First break the shape into two shapes that are both rectangle

The find the length of the line on the tallest part, subtract 30 with 14

30 - 14 = 16

Lets first solve the taller one

16 * 24 = 384

Then solve the one on the left

14 * 15 = 210

Then add the both together to get the total area of the two shapes together

384 + 210 = 594

594 is your answer

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Olegator [25]

$\\ \sf\longmapsto x+4=\sqrt{8-x}$

$\\ \sf\longmapsto (x+4)^2=8-x$

$\\ \sf\longmapsto x^2+16+8x=8-x$

$\\ \sf\longmapsto x^2+8x-x+16-8=0$

$\\ \sf\longmapsto x^2+7x+8=0$

$\\ \sf\longmapsto x^2-8x+x+8$

$\\ \sf\longmapsto (x-8)(x-1)=0$

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Option C

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3 years ago

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lara31 [8.8K]

One of the rules of logarithms is as follows;

$\begin{gathered} \log _ab=x \\ Is\text{ equivalent to,} \\ a^x=b \end{gathered}$

We can now insert the corresponding values in the question provided, as shown below;

$\begin{gathered} \log _2\frac{1}{16}=-4 \\ \text{This is equivalent to,} \\ 2^{-4}=\frac{1}{16} \end{gathered}$

Note that, one of the rules of exponents, states that a number when raised to the power of a negative value, is equivalent to the reciprocal of that expression. An example is shown below;

$a^{-x}=\frac{1}{a^x}$

Therefore, our equation can now be re-written as follows;

$\begin{gathered} 2^{-4}=\frac{1}{16} \\ \frac{1}{2^4}=\frac{1}{16}^{} \\ \frac{1}{16}=\frac{1}{16} \end{gathered}$

However, the question requires the answer to be expressed in exponential form. Therefore,

$\log _2\frac{1}{16}=2^{-4}$

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Answer:

I'm 10, heres how you do it

Step-by-step explanation:

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Hope it helps!

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3 years ago

Please help me find the area​

Please help me find the area