Answer:
not a question. Or did you just do it to teach people
I learnt that calling someone a dirty rat could mean something nice (A nice person that never showers)
Answer:
Washington was nervous about the school succeeding.
Explanation:
From the excerpt, the detail about the early days of a Tuskegee normal school that appears only in this autobiography is "Washington was nervous about the school succeeding."
This is evident when Washington stated that about three months after the school was opened they were having the GREATEST ANXIETY about their work. This implies that Washington and other staff were NERVOUS about the success of the school.
Option C "the original school burned down after it was opened" is not correct and there was nothing like that in that excerpt.
Option D "Washington wanted students to build the new school" is not correct either.
Option B " The school was moved to the site of an old plantation" was closer but not correct either. This is because it is not stated whether the school was eventually moved to the location. It was only stated that the location is what they wanted
The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.
<h3>What is the Nernst Equation?</h3>
The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:
![\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}](https://tex.z-dn.net/?f=%5Cmathbf%7BE_%7Bcell%7D%20%3D%20E_o%20-%20%5Cdfrac%7B0.059%7D%7Bn%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%2B%5D%7D%7B%5BMn%5E%7B2%2B%7D%5D%7D%7D)
where;
- n = Number of electrons = 2
= Initial voltage = 0.77 V
= Cell voltage = 0.78 V
= Manganese concentration = 0.050 M
Replacing the values into the above equation, we have:
![\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7B0.78%20%3D%200.77%20-%20%5Cdfrac%7B0.059%7D%7B2%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
![\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7B0.78%20-0.77%3D%20-0.0296%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
![\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7Blog%5E%7B-1%7D%20%28-0.3378%29%20%3D%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)


Learn more about using the Nernst equation here:
brainly.com/question/24258023
10 images per day. Since it can receive 3 mb per second for 11 hours a day, that’s up to 118,800 megabits it can receive in one day. By multiplying the amount of gigabits in a typical picture (11.2) by the amount of megabits in a gigabit (1024) you get that there’s 11,468.8 megabits in each picture. Lastly, divide the number of megs that the station receives in one day by the amount of megs in a picture, and you get 10 and some change, therefore it can receive up to ten FULL pictures in a day