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2 years ago

Please help me ASAP I will give brainliest

Mathematics

2 answers:

stellarik [79]2 years ago

3 0

Answer:

-23

Step-by-step explanation:

rearrange to point slope form first

slope can be fine by y2-y1/x2-x1 (im using the first 2 points)

so 13-25 = -12 and -54-(-72) = 18, and the slope is -12/18 which is -2/3

then you can use any point (i used the first point) to create the point slope form which is y-ypoint=slope(x-xpoint) and equation would be y-25=-2/3(x+72)

turn it into slope intercept form by multiplying -2/3 within the equation and adding -25 on both sides

you will get y= -2/3x-23

and the y intercept will be (0, -23)

Travka [436]2 years ago

3 0

(o,-23)
This is because the slope is -2/3 and if you graph this it’ll show that the line crosses the y intercept at -23

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Please help and explain please

butalik [34]

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2 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

2 years ago

Match each system of equations to its graph. y = 2x + 1 y = x + 2 y = 3x y = x + 3 y = 2x − 2 y = x − 2 y = 2x + 3 y = x + 5 y =

GalinKa [24]

The matchup are:

(1st picture): y=2x+3 and y=x+5
(2nd picture): y=4x+2 and y =3x+2
(3rd picture): y=2x+1 and y =x+2
(4th picture): 3x and x+3

<h3>What does the graph of an equation shows?</h3>

The graph of the linear equation is known to be one that often brings or set the points that can be found on the coordinate plane and it is one that shows all the solutions to the equation.

Note that when all variables stands for real numbers, a person can be able to use graph to show the equation and this is often done through plotting the points to show a pattern and then link up the points to have all the points.

From the above, the pictures that have all the points as shown on the graph are: