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3 years ago

If f(x) = 3 -3 and g(x) = 3x2 + x – 6, find (f + g)(x).

Mathematics

1 answer:

DanielleElmas [232]3 years ago

3 0

Answer:

Step-by-step explanation:

note that (f + g)(x) = f(x) + g(x) , thus

f(x) + g(x)

= $\frac{x}{2}$ - 3 + 3x² + x - 6 ← collect like terms

= 3x² + $\frac{3}{2}$ x - 9 → D

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What to the power of 4 equles 625

jeyben [28]

Answer:

5^4

Step-by-step explanation:

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3 years ago

How many terms are there in this expression? 3a + b - 4c <br> ——-<br> 3<br> 6<br> 5

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3 years ago

Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?

In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)= $2x^{3}-26x-24$

$2x^{3}-26x-24$ =0

$2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\$

$=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\$

$=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\$

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

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3 years ago

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Nikitich [7]

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3 years ago

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Rudiy27

Answer:

5.888045975

Step-by-step explanation:

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