The complete proof using the AAS congruence postulate and CPCTC is explained below to show that QT ≅ SR.
<h3>What is the AAS Congruence Postulate?</h3>
When two angles of a triangle, and one of its side that is nonincluded are congruent to corresponding two angles and a nonincluded side in the another triangle, then both triangles are congruent by the AAS congruence postulate.
If two triangles are congruent, then all its corresponding parts are also congruent to each other based on the CPCTC theorem.
Below is the two-column proof that proves that side QT is congruent to side SR.
<u>Statement Reasons </u>
1. ∠R ≅ ∠T, QT ≅ SR 1. Given
2. ∠TQS ≅ ∠RSQ 2. Alternate interior angles
3. QS ≅ QS 3. Reflexive property
4. ΔTQS ≅ ΔRSQ 4. AAS
5. QT ≅ SR 5. CPCTC
Learn more about AAS congruence postulate on:
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For this case we have that the quotient of 6 and a number, can be expressed as:
Where the variable "x" represents the incognito number.
Now we have that expression is subtracted from 100. Now, we can write the following:
ANswer:
Option A
Answer:
5. f(x) = -2x² + 3x
f(-3) = -2(-3)² + 3(-3) = -27
f(2) = -2(2)² + 3(2) = -2
f(-a) = -2(-a)² + 3(-a) = -2a² - 3a
-f(a) = -[-2a² + 3a] = 2a² - 3a
f(a + h) = -2(a + h)² + 3(a + h) = -2(a² + 2ah + h²) + 3a + 3h = -2a² - 4ah - 2h² + 3a + 3h
6. f(x) = 2|3x - 1|
f(-3) = 2|3(-3) - 1| = 2*10 = 20
f(2) = 2|3(2) - 1| = 2*5 = 10
f(-a) = 2|3(-a) - 1| = 2|-3a - 1|
-f(a) = -(2|3a - 1|) = -2|3a - 1|
f(a + h) = 2|3(a + h) - 1| = 2|3a + 3h - 1|
Answer:
Step-by-step explanation:
The relative speed of the two trains is the sum of the speeds they are traveling. (If you're on either of the trains, this is the speed you appear to be moving when you see the other train.) In our problem, the relative speed of the two trains is 70 mph + 60 mph = 130 mph. What if the trains were traveling in the same direction? Then we'd need to subtract the speed of the slower train from the speed of the faster train, and their relative speed would be 10 mph.
Answer:
add 37.00 to 432.10. so you get 432.10 + 37.00 = 469.1
