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1 year ago

Identify the lateral area and surface area of a regular triangular pyramid with base edge length 6 cm and slant height 13 cm.

Mathematics

1 answer:

Law Incorporation [45]1 year ago

6 0

The lateral area is 117 square centimeters and the surface area is 292.72 square centimeters

<h3>How to determine the lateral area?</h3>

The given parameters are:

Base length (b) = 6
Slant height (l) = 13

The lateral area is calculated using:

Lateral = 0.5 * (Perimeter of base) * Slant height

This gives

Lateral = 0.5 * (3 * 6) * 13

Evaluate

Lateral = 117

Hence, the lateral area is 117 square centimeters

<h3>How to determine the surface area?</h3>

The surface area is calculated using:

Surface = l²√3

This gives

Surface = 13² * √3

Evaluate

Surface = 292.72

Hence, the surface area is 292.72 square centimeters

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3 years ago

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In △CDE , CD=12 , DE=5 , and m∠E=83∘ .<br><br> What is m∠D to the nearest tenth of a degree?

mr_godi [17]

Answer:

As law of sin:

CD/sinE = DE/sinC

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3 years ago

Point A is located at (3,-6) and point A is located at (1-2). What is the scale factor?

Anuta_ua [19.1K]

Answer:

The scale factor is 3.

Step-by-step explanation:

Let the origin O(0,0) is the reference point and the coordinates of the point A are given by (3,-6).

Therefore, the distance OA is given by $\sqrt{(3 - 0)^{2} + (- 6 - 0)^{2}} = 3\sqrt{5}$ units.

Again, the coordinates of point A' are (1,-2).

Therefore, the distance OA' is given by $\sqrt{(1 - 0)^{2} + (- 2 - 0)^{2}} = \sqrt{5}$ units.

Hence, the scale factor is $\frac{OA}{OA'} = \frac{3\sqrt{5} }{\sqrt{5}} = 3$ . (Answer)

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3 years ago