Question

What is an equation of the line that passes through the points (-5,-1) and (5,3)?

Answer 1

Answer:

The equation of the line is:

$y=\frac{2}{5}x+1$

Step-by-step explanation:

Given the points

• (-5, -1)

• (5, 3)

Finding the slope between points

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-5,\:-1\right),\:\left(x_2,\:y_2\right)=\left(5,\:3\right)$

$m=\frac{3-\left(-1\right)}{5-\left(-5\right)}$

$m=\frac{2}{5}$

Using the point-slope form to find the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 2/5 and the point (5, 3)

$y-3=\frac{2}{5}\left(x-5\right)$

Add 3 to both sides

$y-3+3=\frac{2}{5}\left(x-5\right)+3$

$y=\frac{2}{5}x+1$

Thus, the equation of the line is:

$y=\frac{2}{5}x+1$