C=2
r
A=
r<span>²
C=2</span>
r=58
2r=58
r=29
A=
r<span>²
A=29</span><span>²</span>
A=841
Answer:
50:3
Step-by-step explanation:
7000g:420 both are divisible by 70
1000:60 both are divisible by 10
100:6 both are divisible by 2
50:3
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Answer:
90
Step-by-step explanation:
120 - (120/4)
120 - 30 = 90
Answer:
21
Here’s legitimate proof that 9+10=21
(9 + 10) (base x) = 21 (base y)
9(1) + [1(x) + 0(1)] = 2(y) + 1
Simplify and solve for y:
2y = 8 + x
y = 4 + x/2
Since we have number bases, we want x and y to be positive integers. The term x/2 requires that x be a positive even number.
Also since 9 is in base x, we have x ≥ 10, as the digit 9 would not be used for a base 9 or smaller.
Thus we have the pairs of solutions:
x = 10, so y = 9
x = 12, so y = 10
x = 14, so y = 12
…
x, y = 4 + x/2 … Therefore 9+10=21!
