Question 1:
Slope = 1/5
y = mx + c
y = 1/5 x + c
at point (5, -1)
-1 = 1/5 (5) + c
- 1= 1 + c
c = - 2
y = 1/5x - 2
5y = x - 10
Question 2:
slope = (9-5)/(3-1)
Slope = 2
y = mx + c
y = 2x + c
at point (1, 5)
5 = 2(1) + c
c = 5 - 2
c = 3
y = 2x + 3
√50 + √242 - √2
= √5·5·2 + √11·11·2 -√2
= 5√2 + 11√2 - √2
= 16√2 - √2
= 15√2
First let's find the length of the last side. We can do this by adding AB and BC together, then subtracting this amount from the perimeter of Triangle ABC, 22 cm.
ABC - (AB + BC) ⇒ 22cm - (8cm + 5cm)
22cm - 13cm = 9cm
The hypotenuse is always the longest side of a triangle, so we know that the side we figured out is the hypotenuse. Now we can use the Pythagorean Theorem to see whether the triangle is a right triangle.
Pythagorean Theorem: a² + b² = c², where a and b are legs and c is the hypotenuse.
If a² + b² do equal c², then the triangle is a right triangle.
8² + 5² = 9²
64 + 25 = 81
89 > 81
The triangle is not a right triangle, but we know that it is obtuse since a and b together are longer than c.
Answer:
1)Area; A = ¼πr²
Perimeter; P = πr/2 + 2r
2)A = 19.63 cm²
P = 17.85 cm
3) r = 8.885 cm
4) r = 14 cm
Step-by-step explanation:
This is a quadrant of a circle. Thus;
Area of a circle is πr². A quadrant is a quarter of a circle. Thus;
Formula for Quadrant Area is; A = ¼πr²
A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.
Formula for the quadrant perimeter in the image given is;
P = 2πr/4 + 2r
P = πr/2 + 2r
B) When r is 5 cm;
A = ¼π(5)²
A = 19.63 cm²
P = π(5)/2 + 2(5)
P = 17.85 cm
C) when A is 100cm²:
¼πr² = 100
r² = 100 × 4/π
r² = 78.9358
r = √78.9358
r = 8.885 cm
D) when P = 50 cm.
50 = πr/2 + 2r
50 = (½π + 2)r
r = 50/(½π + 2)
r = 14 cm
The ratio of the shortest sides is 12/5. Multiplying the other two sides of the smaller triangle by that ratio gives 15 and 18, so the ratios of all sides are the same. The triangles are similar.
ABC ~ ZYX
The largest/smallest scale factor is 12/5 = 2.4.
