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![2x + 9 = 5x](https://tex.z-dn.net/?f=2x%20%2B%209%20%3D%205x)
![5x = 2x + 9](https://tex.z-dn.net/?f=5x%20%3D%202x%20%2B%209)
Subtract sides 2x
![- 2x + 5x = - 2x + 2x + 9](https://tex.z-dn.net/?f=%20-%202x%20%2B%205x%20%3D%20-%202x%20%20%2B%202x%20%2B%209)
![3x = 9](https://tex.z-dn.net/?f=3x%20%3D%209)
Divide sides by 3
![\frac{3x}{3} = \frac{9}{3} \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B3x%7D%7B3%7D%20%20%3D%20%20%5Cfrac%7B9%7D%7B3%7D%20%20%5C%5C%20)
![x = 3](https://tex.z-dn.net/?f=x%20%3D%203)
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CHECK :
![2x + 9 = 5x](https://tex.z-dn.net/?f=2x%20%2B%209%20%3D%205x)
![2(3) + 9 = 5(3)](https://tex.z-dn.net/?f=2%283%29%20%2B%209%20%3D%205%283%29)
![6 + 9 = 15](https://tex.z-dn.net/?f=6%20%2B%209%20%3D%2015)
![15 = 15](https://tex.z-dn.net/?f=15%20%3D%2015)
So the value is correct.
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Answer:
x = negative 9/4
Step-by-step explanation:
-2x-11=6x+7
-2x-11+11=6x+7+11
-2x=6x+18
-2x-6x=6x+18-6x
-8x=18
Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Answer:
The answer is y=-1x+8 or you can write it this way y=-x+8 either way will work fine.
Step-by-step explanation:
y=mx+b
m=-1
y-y=m(x-x¹)
y-1=-1(x-7)
y-1=-1x+7
+1 +1
y=-x+8
I hope this helps:)
1. $1.23 per pair
A dozen is 12 so you do 12x7=84
Then you do 103.32 divided by 84 which gives you 1.23
2. His error was doing 103.32 divided by 7 because he thought it was only 7 pairs but it’s 7 dozen.