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algol13
3 years ago
14

Quadrilateral ABCD has vertices at A(0,0), B(0,2), C(6,2), and D(6,0). Find the vertices of the quadrilateral after a dilation w

ith scale factor 3/2.
Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0

Answer:

A=0

B=0,3

C=9,3

D=9,0

Step-by-step explanation:

Multiplies all the vertices bay scale factor 3/2

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How can one halfx − 5 = one thirdx + 6 be set up as a system of equations? 2y + x = −10 3y + x = 18 2y + 2x = −10 3y + 3x = 18 2
Doss [256]

Answer:

2y-x= -10

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Step-by-step explanation:

The correct option is . 2y-x = -10 ,  3y-x = 18

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one third x + 6 = 1/3 *(x+6)

1/2 x-5 = 1/3x+6 =y

y= 1/2x-5

y = 1/3x+6

Now,

y=x/2 -5     equation 1

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By taking L.C.M of the first equation we get:

y=x/2 -5

y= x-10/2

Now multiply both terms by 2.

2y=x-10

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Now lets solve second equation:

Take L.C.M of the second equation:

y = x/3 +6

y=x+18/3

Multiply both sides by 3

3y= x+18

3y-x = 18

Therefore the system of equations we get is:

2y-x= -10

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3 years ago
how many more pairs of parallel sides does a regular octagon have than a regular octagon have than a regular hexagon
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Answer:
f(x) = 7 + 16x -x^2 + 4x^3 - x^4
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