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Flauer [41]
3 years ago
5

Four less than half of a number is 17. find the number

Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0
The answer is 42. Because 17+4=21 and 21 times 2= 42
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Solve for v:<br> -5.5 = 7.3 + v/8
Romashka [77]

-5.5=7.3+v/8

convert decimals to fractions

-11/2=73/10+v/8

multiply both sides by 40

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add the numbers

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answer

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3 years ago
Q+q+q=q+6 help me please
DENIUS [597]

<span>q+q+q=q+6</span>

<span>3q=q+6</span>

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A community bird-watching society makes and sells simple bird feeders to raise money for its conservation activities. The materi
blondinia [14]

Answer:

The required function is: P(x)=-3x^2+78x-360

The price for each feeder to maximize profit should be $13.

The maximum weekly profit is $147

Step-by-step explanation:

Consider the provided information.

Part (A)

The materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each.

Let x be the price per feeder.

Profit = Revenue - cost

So the profit per feeder is x-6

If we increase then for every dollar increase, it loses 3 sales per week.

This can be written as:

30-3(x-10)

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Where x-10 represents the increase in price and 3  represents the decrease in sales per week.

Thus the profit will be:

P(x)=(x-6)(-3x+60)

P(x)=-3x^2+78x-360

Hence, the required function is: P(x)=-3x^2+78x-360

Part (B) What price should the society charge for each feeder to maximize profits? What is the maximum weekly profit?

The above function is a downward parabola so the maximum will occur at vertex.

The x coordinate of the vertex of parabola is: x=\frac{-b}{2a}

Substitute a=-3, b=78 and c=-360 in above.

x=\frac{-78}{2(-3)}=13

Hence, the price for each feeder to maximize profit should be $13.

Now substitute the value of x in P(x)=-3x^2+78x-360

P(x)=-3(13)^2+78(13)-360=$147

Hence, the maximum weekly profit is $147

5 0
3 years ago
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liberstina [14]

1) one is multiple of all positive integers. So, yes it is multiple of all that numbers.

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What is the answer to this
Monica [59]
The answer to this is A.24
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