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telo118 [61]
4 years ago
11

Find p small and blue

Mathematics
1 answer:
Inga [223]4 years ago
8 0

Answer:

P(Small and Blue) = 3/40

Step-by-step explanation:

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1/3 subtracted by 1/4 equals ​
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0.0833333333

Step-by-step explanation:

turn into decimal

0.333333333-0.25

=0.0833333333

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People in _______ careers are "creators." They are creative and enjoy expressing themselves through art, music, dance, writing,
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C is the answer because dance music are all types of art  
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The Great Pyramid is an example of a___ a0_____ a1.
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Triangular Pyramid

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Solve the given initial-value problem. (x + y)2 dx + (2xy + x2 − 2) dy = 0, y(1) = 1
Yuri [45]
Let's check if the ODE is exact. To do that, we want to show that if

\underbrace{(x+y)^2}_M\,\mathrm dx+\underbrace{(2xy+x^2-2)}_N\,\mathrm dy=0

then M_y=N_x. We have

M_y=2(x+y)
N_x=2y+2x=2(x+y)

so the equation is indeed exact. We're looking for a solution of the form \Psi(x,y)=C. Computing the total differential yields the original ODE,

\mathrm d\Psi=\Psi_x\,\mathrm dx+\Psi_y\,\mathrm dy=0
\implies\begin{cases}\Psi_x=(x+y)^2\\\Psi_y=2xy+x^2-2\end{cases}

Integrate both sides of the first PDE with respect to x; then

\displaystyle\int\Psi_x\,\mathrm dx=\int(x+y)^2\,\mathrm dx\implies\Psi(x,y)=\dfrac{(x+y)^3}3+f(y)

where f(y) is a function of y alone. Differentiate this with respect to y so that

\Psi_y=2xy+x^2-2=(x+y)^2+f'(y)
\implies2xy+x^2-2=x^2+2xy+y^2+f'(y)
f'(y)=-2-y^2\implies f(y)=-2y-\dfrac{y^3}3+C

So the solution to this ODE is

\Psi(x,y)=\dfrac{(x+y)^3}3-2y-\dfrac{y^3}3+C=C

i.e.


\dfrac{(x+y)^3}3-2y-\dfrac{y^3}3=C
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Ted won 121 lollipops playing basketball
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He has 30 students in his class
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