The nearest eighth of an inch
![\tt Step-by-step~explanation:](https://tex.z-dn.net/?f=%5Ctt%20Step-by-step~explanation%3A)
In order to solve for both x and y, we need to use the substitution property, where we replace a variable with what we solved for.
![\tt Step~1:](https://tex.z-dn.net/?f=%5Ctt%20Step~1%3A)
Let's solve for y first. Equation (1st one): 8x + 4y = 12. To isolate y, we can first subtract 8x from both sides, and then divide all terms by 4.
![\tt 8x- (8x)+4y=12-(8x)\\4y=12-8x\\4y/4=y\\12/4=3\\-8x/4=-2x\\y=3-2x](https://tex.z-dn.net/?f=%5Ctt%208x-%20%288x%29%2B4y%3D12-%288x%29%5C%5C4y%3D12-8x%5C%5C4y%2F4%3Dy%5C%5C12%2F4%3D3%5C%5C-8x%2F4%3D-2x%5C%5Cy%3D3-2x)
![\tt Step~2:](https://tex.z-dn.net/?f=%5Ctt%20Step~2%3A)
Then, we can solve for x. Let's take the second equation: 3x + y = 3. We take what we solved for in the previous step and plug it into this equation.
![\tt 2x+(3-2x)=3\\2x+3-2x=3\\2x-2x=0\\3-3=0\\0=0\\x=x](https://tex.z-dn.net/?f=%5Ctt%202x%2B%283-2x%29%3D3%5C%5C2x%2B3-2x%3D3%5C%5C2x-2x%3D0%5C%5C3-3%3D0%5C%5C0%3D0%5C%5Cx%3Dx)
![\large\boxed{\tt Our ~final~answer:(x,3-2x)}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Ctt%20Our%20~final~answer%3A%28x%2C3-2x%29%7D)
Both equations are also the same, so the solution = all real numbers for x.
![\tt y=3-2x\\3-2x=3-2x](https://tex.z-dn.net/?f=%5Ctt%20y%3D3-2x%5C%5C3-2x%3D3-2x)
Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
2x+1 , 3x+9
x3+x2+1 , x2+2x−6
x4+x , −x+6
Step-by-step explanation:
hope this helps
Answer:
Step-by-step explanation:
its c