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4 years ago

Explain how to write numbers in expanded form when the number includes a zero?

Mathematics

1 answer:

Alina [70]4 years ago

6 0

Step-by-step explanation:

Expanded notation may be defined as the way of expressing a number by exhibiting its value of each of the digit.

In an expanded notation, the number is always represented as a summation of each of the digit times its place value, while in the expanded form, an addition is used between the place value numbers.

A number containing zero can be written in the expanded form as for example,

509,300

Since digit 5 is 100,000th place, 9 is in 1,000th place and the digit 3 is 100th place, the number can be written as --

5 x 100,000 + 9 x 1,000 + 3 x 100

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zhenek [66]

Answer:A

Step-by-step explanation:this is not true

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3 years ago

For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec

telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

$4sin(x^2) = 0$

$sin(x^2) = 0$

$x^2 = n\pi$ where n = 0, 1, 2,3, 4, 5,...

$x = \sqrt(n\pi)$

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

$f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0$

$xcos(x^2) = 0$

$x = 0$ or

$cos(x^2) = 0$

$x^2 = \frac{\pi}{2} + n\pi$ where n = 0, 1, 2, 3

$x = \sqrt{\pi(n+1/2)}$

Since we are restricting x between 0 and 3 we can stop at n = 2

So our critical points are at

x = 1.25, $y = f(1.25) = 4sin(1.25^2) = 4$

x = 2.17 , $y = f(2.17) = 4sin(2.17^2) = -4$

x = 2.8, $y = f(2.8) = 4sin(2.8^2) = 4$

For the inflection point, we can take the 2nd derivative and set it to 0

$f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0$

$cos(x^2) = 2x^2sin(x^2)$

$tan(x^2) = \frac{1}{2x^2}$

We can solve this numerically to get the inflection points are at

x = 0.81, $y = f(0.81) = 4sin(0.81^2) = 2.44$

x = 1.81, $y = f(1.81) = 4sin(1.81^2) = -0.54$

x = 2.52, $y = f(2.52) = 4sin(2.52^2) = 0.27$

3 0

3 years ago

A teacher decides to purchase a new car and considers two options. Option one is the new Zoomba for $60,000 with an expected dep

Igoryamba

Don’t now the answer but 60000 2% would be 1200 times 12 time 3 would be 43200$ for the 60k one and then 200 a month would be 7200 for three years that’s all I know

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3 years ago

A line passes through (2, 9) and has a zero slope. Write an equation of the line satisfying the given conditions.

zubka84 [21]

Okay so for finding the equation of a line, which is a function, the equation is set to y, so you can eliminate A and B. When the slope of an equation is 0, we are saying that the y value of any point of the line is going to be the same, which is 9 from the given point (2,9).

So the answer is C. y=9

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3 years ago

Help please

Digiron [165]

Answer:

Option C.

Step-by-step explanation:

Shortest way to solve this question is to find the factors of the given expression.

The given expression is (x² + 13).

Now we have to factorize it.

(x² + 13) = x² + (√13)²

= x² + [-(i)²√(13)²] [Since i = √(-1)]

= x² - (i√13)²

= (x - i√3)(x + i√3) [Since (a² - b²) = (a + b)(a - b)]

Option C will be the answer.

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3 years ago

Explain how to write numbers in expanded form when the number includes a zero?​

Explain how to write numbers in expanded form when the number includes a zero?