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I’d be happy to answer this but I am confused about your question
Answer:
1.2124
2.1212 is the correct answer right
Answer:
distance S = 0.3443 m
Explanation:
given data
mass m = 5 kg
constant acceleration a = 10 seconds
force f = 0.22 N
distance = 3 meter
solution
we will apply Newton's second law
and we find here acceleration of the crate that is
acceleration a = ............1
acceleration a =
acceleration a = 0.044 m/s²
now we get here velocity of crate just before running off edge
v = u + at ...........2
v = 0 + 0.044 × 10
velocity v = 0.44 m/s
and
now we get here time taken for that flight is as
h = 0.5 × gt² ..............3
3 = 0.5 × 9.8× t²
time t = 0.7825 seconds
and horizontal distance will be here
distance S = vt
distance S = 0.44 × 0.7825
distance S = 0.3443 m