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2 years ago

8

Confused so help needed. On a number line where would 6/10 be located choose all answers that make a true statement

1 answer:

Sonja [21]2 years ago

8 0

Answer:

A,B, C are right!

Step-by-step explanation:

If you were to plot those numbers on the line, it would be true!

Good Luck!!!!!

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To win at LOTTO in a certain state, one must correctly select 6 numbers from a collection of 52 numbers (1 through 52). The orde

miv72 [106K]

Answer:

The answer is 20,358,520

Step-by-step explanation:

Selecting 6 numbers from a collection of 52 numbers regardless of order involves a combination.

Note: if regards was taken into order of selection, this would be a permutation.

Hence, the different 6 number selections out of 52 is

52C6 = 52! / [6!*(52-6)!]

= 52!/(6!*46!)

= 20,358,520

7 0

2 years ago

Jarvis left out a statement from the proof shown.which statement is best explained by the corresponding angles postulate

Salsk061 [2.6K]

The postulate of the corresponding angles establishes that when a transversal line cuts two parallel lines, the corresponding angles are congruent. These angles are on the same side of the parallel lines and on the same side of the transversal line.

Then, if we based on this definition and analize the figure attached, we can notice that the angles ∠1 and ∠3 are corresponding angles, so they are congruent. In this case the angle ∠1 is internal and the angle ∠3 is external.

The answer is: ∠1 and ∠3 are congruent (See the image attached).

7 0

3 years ago

Read 2 more answers

Find the value of z in the figure below.<br>.

zzz [600]

answer

z = 100

opposite angles

when inscribed in a circle, the opposite angles of a quadrilateral add up to 180

so z + 80 = 180 and y + 120 = 180

solve for z

z + 80 = 180

z = 180 - 80

z = 100

3 0

2 years ago

a car uses 9.5 L petrol per 100km a) determine the rate in km/L b) how far can the car travel with 47,5L petrol c) how many litr

Lana71 [14]

Step-by-step explanation:

a) determine the rate in km/L

==> 9.5 L/100km = 10.526316 km/L

b) how far can the car travel with 475L petrol

==> 0.210526315789473km/l

c) how many litres of petrol do they need to travel 350 km

==>Liters per km (l/km)2.86×10-3

Liters per 10 km (l/10 km)0.03

Liters per 100 km (l/100km)0.29

Kilometer per liter (km/l)350

6 0

1 year ago

Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0

2 years ago