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Inga [223]
3 years ago
8

Confused so help needed. On a number line where would 6/10 be located choose all answers that make a true statement 

Mathematics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

A,B, C are right!

Step-by-step explanation:

If you were to plot those numbers on the line, it would be true!

Good Luck!!!!!

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I’ll award you brainliest if you answer This question
guajiro [1.7K]

Answer:

$2353 at 12.5% and $7647 at 8.25%

Step-by-step explanation:

I'll say a is the amount he invested in one market, and b is the amount in the other.

a + b = 10000, or b = 10000 - a

multiplying the investments with the percentages and adding them together will give the total earned interest.

(a × 0.125) + (b × 0.0825) = 925

0.125a + 0.0825b = 925

Use substitution to solve for a.

0.125a + 0.0825(10000 - a) = 925

0.125 a + 825 - 0.0825a = 925

0.0425a = 100

a = 2352.94

Use substitution to find b

b = 10000 - 2352.94

b = 7647.06

The questions are to the nearest dollar so round a and b.

$2353 and $7647

6 0
3 years ago
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
4 years ago
In a survey of his neighborhood, Timothy found out that 3 families out of 7 have a dog for a pet. If this ratio is true for the
frozen [14]

Answer:

1650 families

Step-by-step explanation:

In a survey of his neighborhood, Timothy found out that 3 families out of 7 have a dog for a pet.

The given ratio = 3:7

When written as a fraction = 3/7

The number of families that would have a pet dog in a town with about 3,850 families is given as:

3/7 × 3,850

= 1650 families

Therefore, 1650 families would have a pet dog in town.

4 0
3 years ago
What is the quotient-8x^6/4x^-3
Leokris [45]

\dfrac{-8x^6}{4x^{-3}}=-\dfrac{8}{4}x^{6-(-3)}=-2x^{6+3}=\boxed{-2x^9}

Used\ \dfrac{a^n}{a^m}=a^{n-m}

4 0
4 years ago
How do i even do this ? plz help smarties
enot [183]

x = number of messages sent or received

y = total cost per month

Plan A costs $30 per month plus $0.10 per text message. So the cost for plan A is y = 0.10*x + 30. The portion 0.10*x represents just the cost of the 10 cents per message, and then we add on the fixed cost of $30 to get the total cost.

In a similar fashion, plan B's cost is y = 60. There is no cost per message, so we don't have to include x in the picture. The cost is a flat fee, which leads to a flat horizontal line graph (as shown in the attachment below)

Our two equations are: y = 0.10x+30 and y = 60. Let's use substitution to find x

y = 0.10x + 30

60 = 0.10x + 30 ... replace y with 60 (works because y = 60)

60-30 = 0.10x

30 = 0.10x

0.10x = 30

x = 30/0.10

x = 300

If you send or receive 300 messages, then both plans will cost the same. We can see this on the graph below where the two lines cross at (300,60). Note how plugging x = 300 into the first equation simplifies to y = 60.

3 0
4 years ago
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