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Inga [223]
3 years ago
8

Confused so help needed. On a number line where would 6/10 be located choose all answers that make a true statement 

Mathematics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

A,B, C are right!

Step-by-step explanation:

If you were to plot those numbers on the line, it would be true!

Good Luck!!!!!

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which qaudratic equation is equivalent to (x+2)^2+5(x+2)-6=0 a. (u+2)^2+5(u+2)-6=0 where u=(x-2) b. u^2+4+5u-6=0 where u= (x-2)
Lisa [10]

Answer:

D

Step-by-step explanation:

Given

(x + 2)² + 5(x + 2) - 6 = 0

Using the substitution u = x + 2 , then the equation can be expressed as

u² + 5u - 6 = 0 → D

5 0
3 years ago
The graph of a linear relation passes through the point (-2,7) and has a slope of 1/6.
docker41 [41]

Answer:

Step-by-step explanation:

eq. of any line withslope 1/6 is

y=1/6x+c

∵ it passes through (-2,7)

so 7=1/6(-2)+c

c=7+1/3=22/3

eq. of line is

y=1/6x+22/3

6 0
3 years ago
Read 2 more answers
The height of a wooden pole, h, is equal to 20 feet. A taut wire is stretched from a point on the ground to the top of the pole.
kykrilka [37]

ANSWER

D. 25 feet

EXPLANATION

The height of the wall,h, the taut wire and the distance from the base of the pole to the point on the ground, formed a right triangle.

According to the Pythagoras Theorem, the sum of the length of the squares of the two shorter legs equals the square of the hypotenuse.

Let the hypotenuse ( the length of the ) taught wire be,l.

Then

{l}^{2}  =  {h}^{2}  +  {b}^{2}

{l}^{2}  =  {20}^{2}  +  {15}^{2}

{l}^{2}  =  400 + 225

{l}^{2}  =  625

l=  \sqrt{625}  = 25ft

8 0
3 years ago
Petra jogs 5 miles in 40 minutes at the rate how long would it take her to jog 11 miles
KatRina [158]
88 minutes (1 hour and 28 mins)

Since 5 miles takes 40 minutes, multiplying both numbers by 2 gets you to 10 miles in 80 minutes. To get the extra 1 more miles you have to find the unit rate

5 miles in 40 minutes : divided both numbers by 5 to get
1 mile in 8 minutes
add the one mile in 8 minutes to the 10 miles in 80 mins and you get 11 miles in 88 minutes
6 0
3 years ago
Three consecutive odd integers have a sum of 27. Find the integers.
jek_recluse [69]

\sf \bf {\boxed {\mathbb {GIVEN:}}}

Sum of three consecutive odd integers = 27

\sf \bf {\boxed {\mathbb {TO\:FIND:}}}

The values of the three integers.

\sf \bf {\boxed {\mathbb {SOLUTION:}}}

\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}

\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

Let us assume the three consecutive odd integers to be x, (x+2) and (x+4).

As per the condition, we have

Sum \:  \:  of \:  \:  the  \:  \: three \:  \:  consecutive \:  \:  odd \:  \:  integers  = 27

➺ \: x + (x + 2) + (x + 4) = 27

➺ \: x + x + 2 + x + 4 = 27

Now, collect the like terms.

➺ \: (x + x + x) + (2 + 4) = 27

➺ \: 3x + 6 = 27

➺ \: 3x = 27 - 6

➺ \: 3x = 21

➺ \: x =  \frac{21}{3} \\

➺ \: x = 7

Therefore, the three consecutive odd integers whose sum is 27 are \boxed{  7  }, \boxed{ 9   } and \boxed{ 11   } respectively.

\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}

⇢ 7 + 9 + 11 = 27

⇢ 27 = 27

⇢ L. H. S. = R. H. S.

\sf\blue{Hence\:verified.}

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}

4 0
3 years ago
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