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Juliette [100K]
2 years ago
14

The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either

from Rome, Italy, or New York, New York: High Low Q1 Q3 IQR Median Mean Ď Rome 18 1 3 7 4 6. 5 6. 4 4. 3 New York 14 1 4. 5 8. 5 4 2005. 5 6. 1 3. 2 Which of the choices below best describes how to measure the center of these data? Both centers are best described by the mean. Both centers are best described by the median. The Rome data center is best described by the mean. The New York data center is best described by the median. The Rome data center is best described by the median. The New York data center is best described by the mean.
Mathematics
1 answer:
kompoz [17]2 years ago
4 0

The Rome data center is best described by the mean. The New York data center is best described by the median. The third option C is correct.

<h3>The Mean and Median:</h3>

The mean of a data set is the average of all the terms in the data set. The median of a data set is the value of the midpoint term in the frequency distribution.

From the given information, the table can be better expressed as:

           High   Low   Q1     Q3    IQR   Median    Mean         σ

Rome   18         1        3       7        4         6.5        6.4           4.3

NY        14         1       4.5    8.5      4        5.5        6.1            3.2

  • From the data sets in the table, the distribution for Rome is not largely diverse, and there isn't much departure from the mean value. It indicates that in the data set of Rome families, no outliers have occurred.

  • In New York, the data indicate a distinct outlier for New York families in Q3. This is due to the fact that the gap is so large, the mean may not be a good choice for determining the measure of the central tendency.

Therefore, we can conclude that, the Rome data center is best described by the mean and the median will be utilized to determine the central tendency in New York.

Learn more about mean and median here:

brainly.com/question/14532771

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Object is thrown upward from a height of 15 ft at an initial vertical velocity of 30 ft per second. How long will it take to hit
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Step-by-step explanation:

We'll begin by calculating the time taken for the object to get to the maximum height from the point of projection. This can be obtained as follow:

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Final velocity (v) = 0 ft/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s² = 3.28084 × 9.8 = 32.15 ft/s²

Time (t₁) to reach the maximum height from the point of projection =?

v = u – gt₁ (since the object is going against gravity)

0 = 30 – (32.15 × t₁

0 = 30 – 32.15t₁

Collect like terms

0 – 30 = – 32.15t₁

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Divide both side by – 32.15

t₁ = –30 / –32.15

t₁ = 0.93 s

Next, we shall determine the maximum height reached by the object from the point of projection.

This can be obtained as follow:

Initial velocity (u) = 30 ft/s

Final velocity (v) = 0 ft/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s² = 3.28084 × 9.8 = 32.15 ft/s²

Maximum height (h) reached from the point of projection =?

v² = u² – 2gh (since the object is going against gravity)

0² = 30² – (2 × 32.15 × h)

0 = 900 – 64.3h

Collect like terms

0 – 900 = – 64.3h

– 900 = – 64.3h

Divide both side by – 64.3

h = –900 / –64.3

h = 14 ft

Thus, the maximum reached by the object from the point of projection is 14 ft.

Next, we shall determine the height to which the of object is located from the maximum height reached to the ground. This can be obtained as follow:

Height (h₀) from which the object was projected = 14 ft

Maximum Height (h) reached from the point of projection = 14 ft

Height (hₗ) to which the of object is located from the maximum to the ground =?

hₗ = h₀ + h

hₗ = 14 + 14

hₗ = 28 ft

Thus, the height to which the of object is located from the maximum reached to the ground is 28 ft.

Next, we shall determine the time taken for the object to get to the ground from the maximum height reached. This can be obtained as follow:

Height (hₗ) to which the of object is located from the maximum to the ground = 28 ft

Acceleration due to gravity (g) = 9.8 m/s² = 3.28084 × 9.8 = 32.15 ft/s²

Time (t₂) taken for the object to get to the ground from the maximum height reached =?

hₗ = ½gt₂²

28 = ½ × 32.15 × t₂²

28 = 16.075 × t₂²

Divide both side by 16.075

t₂² = 28 / 16.075

Take the square root of both side

t₂ = √(28 / 16.075)

t₂ = 1.32 s

Finally, we shall determine the time take for the object to get to the ground from the point of projection. This can be obtained as follow:

Time (t₁) to reach the maximum height from the point of projection = 0.93 s

Time (t₂) taken for the object to get to the ground from the maximum height reached = 1.32 s

Time (T) take for the object to get to the ground from the point of projection =?

T = t₁ + t₂

T = 0.93 + 1.32

T = 2.25 s.

Therefore, the time take for the object to get to the ground from the point of projection is 2.25 s.

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