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3 years ago

If we divide 2 and 6 by 2 what is our new simplified ratio?

Mathematics

2 answers:

Temka [501]3 years ago

4 0

3.600000 is the answer I hope this helps

garik1379 [7]3 years ago

3 0

Answer:

Step-by-step explanation:

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Emily is entering a bicycle race for charity. Her mother pledges $0.80 for every 0.25 mile she bikes. If Emily bikes 5 miles, ho

e-lub [12.9K]

Answer:

i think the answer is one of the two answers $16 or $20.50. Sorry if it is wronge.

8 0

3 years ago

-3 1/5+(-6 1/2) please help quickly

Ksivusya [100]

Answer:

Exact Form:

-97/10

Decimal Form:

−9.7

Mixed Number Form:

-9 7/10

8 0

3 years ago

Read 2 more answers

It costs $36.76 for 3 tickets to visit the science center. It costs $51 for 4 tickets to visit the zoo. Which attraction will co

NeX [460]

Answer:

The zoo will cost more money for a group of 12 students to visit.

Step-by-step explanation:

First, you have to divide the costs by the amount of tickets to find out how much you would have to pay for one ticket.

Science Center: $36.76 ÷ 3 = $12.25

Zoo: $51 ÷ 4 = $12.75

Then, the cost for one ticket should be multiplied by 12, the group of students wanting to visit.

Science Center: $12.25 x 12 = $147.04

Zoo: $12.75 x 12 = $153

Comparing the prices, you will see that the zoo will cost $5.96 more dollars than the science center.

4 0

3 years ago

Read 2 more answers

Juan crosses out the numbers that are less than 45 and greater than 50. Circle the numbers that are left.

DIA [1.3K]

Answer:

49 and 46

Step-by-step explanation:

because they are greater than 45 but less than 50.

6 0

3 years ago

Let F be the event that a student is enrolled in a finance course, and let S be the event that a student is enrolled in a statis

Inessa [10]

Answer:

0.375

Step-by-step explanation:

Given that F is the event that a student is enrolled in a finance course, and let S be the event that a student is enrolled in a statistics course.

It is known that 40% of all students are enrolled in a finance course and 35% of all students are enrolled in statistics. Included in these numbers are 15% who are enrolled in both statistics and finance.

P(F) = 0.40: P(S) = 0.35: P(FS) = 0.15

A student is randomly selected, and it is found that the student is enrolled in finance.

Probability that this student is also enrolled in statistics/ student is enrolled in finance.

= $\frac{P(FS)}{P(F)} \\=\frac{0.15}{0.40} \\=0.375$

(Using conditional probability formula)

5 0

3 years ago