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Otrada [13]
3 years ago
12

What is the slope and y-intercept from the table below?

Mathematics
1 answer:
Nataliya [291]3 years ago
4 0

Answer:

The equation is y = -5x + 55

Slope = -5

y-intercept = 55

Step-by-step explanation:

The given table shows the different coordinates of points on a straight line.

The general equation of a line is y = mx + b

where m is the slope and b is the y intercept.

Actually , here only 2 values are needed but there are 4 values                       given which is just to check whether our line is correct or not.

Substitute values of x and y in the equation.

Put (1,50),

50 = m + b    ----------(1)

Put (2,45),

45 = 2m + b    -----------(2)

Solve (1) and (2),

Slope , m = -5

y-intercept , b = 55

Hence , the equation is y = -5x + 55.

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Which of the following best describes the graph of the polynomial function below?
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Answer:

A. The graph has two zeroes.

Step-by-step explanation:

A <em>zero of a polynomial</em> is a value of x that makes the polynomial equal to zero.

In other words, it is <em>an x-intercept</em>.

The graph crosses the x-axis twice, so there are two zeroes.

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3 years ago
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Divide £250 in the ratio 3:6:1
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Answer:

Step-by-step explanation:

The numbers in the ratio add up to 10. So divide 250 by 10. One part is £25. Multiply by the given numbers: 3x25=75. 6x25=150. 1x25=25. So you have £75:£150:£25.

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3 years ago
Find the area of a square whose side is 4xy.​
ruslelena [56]

Step-by-step explanation:

Given,

Side of a square = 4xy

Therefore, area of the square = side × side

= 4xy × 4xy

16 {x}^{2}  {y}^{2} (ans)

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How do you know how many places are in fifty million without writing the number in standard form
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3 years ago
What is the equation of the circle with center (4, 4) that passes through the point (10, 14)? HELP MEEEEE PLEASE
Gemiola [76]

Answer:

The equation of the circle can be written as:

  • \left(x-4\right)^2+\left(y-4\right)^2=136

Step-by-step explanation:

The general equation of a circle with center (h,k) and radius r is:

\left(x-h\right)^2+\left(y-k\right)^2=r^2

In our example, we know \left(h,k\right)=\left(4,4\right), as we just have to make sure we need determine \:r^2.

\left(x-4\right)^2+\left(y-4\right)^2=r^2\:\:

As the circle passes through (10, 14), that pair of values for x and y must satisfy the equation. So we have:

\left(10-4\right)^2+\left(14-4\right)^2=r^2

\mathrm{Switch\:sides}

r^2=\left(10-4\right)^2+\left(14-4\right)^2

r^2=6^2+10^2

r^2=36+100

r^2=136

Thus the equation of the circle can be written as:

\left(x-4\right)^2+\left(y-4\right)^2=136

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