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Otrada [13]
3 years ago
12

What is the slope and y-intercept from the table below?

Mathematics
1 answer:
Nataliya [291]3 years ago
4 0

Answer:

The equation is y = -5x + 55

Slope = -5

y-intercept = 55

Step-by-step explanation:

The given table shows the different coordinates of points on a straight line.

The general equation of a line is y = mx + b

where m is the slope and b is the y intercept.

Actually , here only 2 values are needed but there are 4 values                       given which is just to check whether our line is correct or not.

Substitute values of x and y in the equation.

Put (1,50),

50 = m + b    ----------(1)

Put (2,45),

45 = 2m + b    -----------(2)

Solve (1) and (2),

Slope , m = -5

y-intercept , b = 55

Hence , the equation is y = -5x + 55.

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kvv77 [185]

Answer:

x = \frac{mp + e}{t}

Step-by-step explanation:

times p on both sides

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3 years ago
What is the greatest integer solution of 5-3m<11
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8 0
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How do you solve this 2x +5 - 7x = 15
Serga [27]
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Is this correct ? if not what’s the correct answer?
navik [9.2K]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
a gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sel
adell [148]

Answer:

The price per wind chime that will maximize revenue = $ 315

Step-by-step explanation:

Given - A gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sell 5 fewer wind chimes per month.

To find - Find the price per wind chime that will maximize revenue.

Proof -

Given that,

Total Wind chimes selling = 160

Price of each Wind chime = $150

Now,

Given that, for each $15 increase in price, they will sell 5 fewer wind chimes per month.

So,

Let the price = 150 + 15x

So,

Number of wind Chimes sold per month = 160 - 5x

So,

Total Revenue, R = (150 + 15x)(160 - 5x)

                             = 24000 - 750x + 2400x - 75x²

                             = 24000 + 1650x - 75x²

⇒R(x) = 24000 + 1650x - 75x²

Differentiate R with respect to x , we get

R'(x) = 1650 - 150x

Now,

For Maximize Revenue, Put R'(x) = 0

⇒1650 - 150x = 0

⇒150x = 1650

⇒x = 1650/150

⇒x = 11

∴ we get

Price per Wind chime = $ 150 + 15(11)

                                    = $ 150 + 165

                                    = $ 315

So,

The price per wind chime that will maximize revenue = $ 315

3 0
3 years ago
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