Answer:
Step-by-step explanation:
first option
Answer:
-1 1/3
Step-by-step explanation:
Answer:
![\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles](https://tex.z-dn.net/?f=%5Ctexttt%7BSubmarine%27s%20depth%20relative%20to%20sea%20level%20after%20the%20first%20minute%20%3D%7D-%5Cfrac%7B4%7D%7B15%7Dmiles)
Step-by-step explanation:
Starting at sea level, a submarine descended at a constant rate to a depth of −4/5 mile relative to sea level in 3 minutes.
Total time = 3 minutes
![\texttt{Total depth descended in 3 minutes =}-\frac{4}{5}miles](https://tex.z-dn.net/?f=%5Ctexttt%7BTotal%20depth%20descended%20in%203%20minutes%20%3D%7D-%5Cfrac%7B4%7D%7B5%7Dmiles)
We need to find what was the submarine's depth relative to sea level after the first minute,
![\texttt{Depth descended in per minute =}\frac{-\frac{4}{5}}{3}=-\frac{4}{15}miles](https://tex.z-dn.net/?f=%5Ctexttt%7BDepth%20descended%20in%20per%20minute%20%3D%7D%5Cfrac%7B-%5Cfrac%7B4%7D%7B5%7D%7D%7B3%7D%3D-%5Cfrac%7B4%7D%7B15%7Dmiles)
![\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}\times 1=-\frac{4}{15}miles\\\\\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles](https://tex.z-dn.net/?f=%5Ctexttt%7BSubmarine%27s%20depth%20relative%20to%20sea%20level%20after%20the%20first%20minute%20%3D%7D-%5Cfrac%7B4%7D%7B15%7D%5Ctimes%201%3D-%5Cfrac%7B4%7D%7B15%7Dmiles%5C%5C%5C%5C%5Ctexttt%7BSubmarine%27s%20depth%20relative%20to%20sea%20level%20after%20the%20first%20minute%20%3D%7D-%5Cfrac%7B4%7D%7B15%7Dmiles)
So 45/6
to make it easier, you can simplify by finding the 'ones' exg 4/8=1/2 because 1/2 times 4/4=4/8
45/6=15/2 times 3/3=15/2 and 15 is close to 14 so 14/2=7 and 1/2=.5 so
7.5 is the answer
Answer:
Step-by-step explanation:
2/sin25=AB/sin90
AB=4.73