Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
Answer:
Perimeter = 36.8 ft
Step-by-step explanation:
<u>Step 1: Add the straight sides together</u>
3+3+3+3+3+3 = 18 ft
<u>Step 2: Find the perimeter of the semi-circles</u>
The formula for the perimeter of semi-circle: 1/2 π × d
Diameter = 12 - 3 - 3 = 6, because the whole length is 12 minus the 6 ft of other stuff.
Now, 1/2π * 6 = 9.4 ft
But, there are two semi-circles so it will be 9.4 + 9.4 = 18.8 ft
<u>Step 3: Add all of them</u>
18 + 18.8 = 36.8 ft
Answer:
C
Expand the bracets then simplfy and then factorise
Answer:
slope of line ax + by = c is -a/b
so, slope of 7x +2y =5 is -7/2
