If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Good morning
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Answer:
2/3 < 3/4
___________________
Step-by-step explanation:
2/3 = (2*4)/(3*4)=8/12
3/4 = (3*3)/(4*3)=9/12
Since 9/12>8/12 then 3/4>2/3
:)
Hello :
<span> the axis of symmetry is the line for equation : x = 2
the </span><span>vertex is the point : A (2 , 4)</span>
Answer:
12 servings!
Step-by-step explanation:
1/4 equals 0.25 gallons, 1/2 gallons is 0.5, so Will will have a mix of 0.75 gallons. If each serving is 1/16 and 1/16 equals 0.0625, divide 0.75 by 0.0625 = 12 servings.
Answer:
x = 4/15 and x= 10/3
Step-by-step explanation:
|9x-7|=|6x+3|
There are two solutions, one positive and one negative.
(9x-7)=6x+3 - (9x-7)=6x+3
We will take the positive one first
(9x-7)=6x+3
Subtract 6x from each side
(9x-6x-7)=6x-6x+3
3x -7=3
Add 7 to each side
3x-7+7 = 3+7
3x = 10
Divide by 3x/3 = 10/3
x = 10/3
Now we will take the negative solution
- (9x-7)=6x+3
Distribute the negative sign
-9x+7 = 6x+3
Add 9x to each side
-9x+9x+7 = 6x+9x+3
7 = 15x+3
Subtract 3 from each side
7-3 = 15x +3-3
4 = 15x
Divide by 15 on each side
4/15 =15x/15
4/15 =x
