120 inches cubed
4*10*3 is 120
The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.
We want angle x, which is opposite the side of length 39.
Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x
or 1521 = 3481 + 1296 - 2(36)(59) cos x
Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x
-3256 = -4248cos x
-3256
Then: cosx = --------------- = 0.766
-4248
Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)
Answer: lise will play 2 times deanna will play 4 times
Step-by-step explanation:
Divide 4w to every term separately.


48/4 = 12
w^3/w = w^2
So our first term is 12w^2.
128/4 = 32
w^2/w = w
So our second term is 32w.
4w/4w = 1
Anything divided by itself is 1.
-1/4w, this can't be simplified further, so this is our last term.
So we have:
Answer:−9a+10b−23
Step-by-step explanation:−9a+3b−a+7b−13+a−10
Combine −9a and −a to get −10a.
−10a+3b+7b−13+a−10
Combine 3b and 7b to get 10b.
−10a+10b−13+a−10
Combine −10a and a to get −9a.
−9a+10b−13−10
Subtract 10 from −13 to get −23.
−9a+10b−23