Answer:
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I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation:
Answer: 
Step-by-step explanation: Given expression
.
In order to find the product of given expression, we need to convert 5,600,000 into scientific notation, because other number is also in scientific notation.
5,600,000 = 5.6 × 10^6.
Therefore,
.
Now, multiplying 5.63 × 5.6 first, we get 31.528.
And 10^5 × 10^6 = 10^11.
Therefore,
.
<h3>Or 3.1528 × 10^12.</h3>
Suppose x books are produced by both methods.
Total cost for method 1 = 60346 + 10.5x
Total cost for method 2 = 18682 + 21x
Cost of method 1 = Cost of method 2
60346 + 10.5x = 18682 + 21x
60346 - 18682 = 21x - 10.5x
41664 = 10.5x
x = 41664/10.5
x = 3968
For 3968 books produced the cost by both methods will be the same.