Answer:
Not a Solution
Step-by-step explanation:
We are given two inequalities which are
y ≤ x -4 .............(i)
-x+3y>-4 ............(ii)
Also we are given an ordered pair which is (5, 1/3)
Now from this order pair we see that
x = 5 and y = 1/3
Because in an ordered pair the first element represents the x value while the second value represent the y value
Now to find whether this order pair satisfies the given inequality or not we have to plugin the values of x and y in both inequalities separately and see whether it satisfies the in equality or not
Taking First inequality:
which is
y ≤ x -4
Putting x = 5 and y = 1/3 in inequality
it becomes
≤ 5 -4
≤ 1 ∵ which is true
So this inequality holds the order pair
Taking second inequality:
which is
-x+3y> -4
Putting x = 5 and y = 1/3 in inequality
it becomes
-5+
> -4
-5+1 >-4
-4>-4 ∵ which is false because - 4 = - 4
So this inequality does not holds the order pair
So the order pair is not solution of the given inequalities because of the reason that second inequality is not satisfied
Answer:
Step-by-step explanation:
The answer id D, ^3 sqrt x^9 times x
Answer:
5, 5, 8, 8, 9, 0, 0, 3, 3, 9, 1, 5
Step-by-step explanation:
I THINK THAT'S RIGHT, BUT HAVE A GOOD DAY NEW BESTIE <3
Below are the choices that can be found elsewhere:
<span>A. rectangle; P = 26 linear units
B. square; P = 42 units2
C. parallelogram; P = 42 linear units
D. trapezoid; P = 26 linear units
The answer is A which is r</span>ectangle; P = 26 linear units
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Hello,
(u+v)^4= u^4+4^3v+6u²v²+4uv^3+v^4
with u=2x² and v=y²
(2x²+y²)^4=
16x^8 + 32x^6*y² +24x^4y^4 +8x²y^6 + y^8