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Studentka2010 [4]
3 years ago
8

What is the 7th term in the sequence below?

Mathematics
1 answer:
enot [183]3 years ago
5 0

Answer:

C

my answer is the image above

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What shape is a rhombus related to and why​
Ksju [112]
A rhombus is related to a “Parallelogram”

Why? - because it fulfills the requirements of a parallelogram: a quadrilateral with two pairs of parallel sides. It goes above and beyond that to also have four equal-length sides, but it is still a type of parallelogram.

hope this helped <3
8 0
3 years ago
Please help<br><br><br><br> ?? <br><br><br><br><br><br> :$):’jfidifkvk
Marianna [84]

Answer:

For the question a i think its b

Step-by-step explanation:

4 0
3 years ago
The sum of two numbers is 240. If one number is twice the other number, find the two numbers.
Deffense [45]

Answer:

The sum of two numbers is 240. The larger number is 6 less than twice the smaller. Find the numbers.

----------

Let the smaller be "x" ; Larger is "2x-6"

EQUATION:

x + 2x-6 = 240

3x= 246

x = 82 (smaller)

2x-6 = 158 (larger)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Help please!!!!! (QUESTION #3)!!!!!!!
Paha777 [63]
I’m not sure I’m just guessing but maybe 7x minus 35
7 0
3 years ago
Car A has an initial value of 30,000 and depreciates at a rate of 20% per year. Car B has an initial value of 20,000 and depreci
Doss [256]

Answer:

The value of Car B will become greater than the value of car A during the fifth year.

Step-by-step explanation:

Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.

In the attached excel file, the following are used:

Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000

Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000

Annual Depreciation expense of Car B in Year 7 =  Beginning value of Car B in Year 7 = 2,000

Conclusion

Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.

Download xlsx
4 0
3 years ago
Read 2 more answers
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