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luda_lava [24]
3 years ago
6

-5 + 4 on a number line

Mathematics
1 answer:
alexandr402 [8]3 years ago
7 0
-1 is the answer homie
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The wading pool shown is a trapezoidal prism with a total volume of 286 cubic feet. What is the missing dimension? First base: 8
harkovskaia [24]
To find the missing dimension you will use the formula for finding the volume of a prism and solve for the missing dimension.  In this case 2ft is how deep the pool is and you will solve for the width of the pool.

V = Bh, where B is the area of the base.  In this case, use the area of a trapezoid formula.

286 = 1/2h(8 +13)2
<u>286</u> = <u>21h</u>
21      21
h = 13.6

The width of the wading pool is approximately 13.6 feet.
5 0
3 years ago
G/3 + 11 = 25 please help​
pochemuha

Answer: g = 42

Step-by-step explanation:

g/3 + 11 = 25

First, subtract 11 to both sides

g/3 = 14

Then, multiply 3 to both sides to get rid of the fraction

g=42

8 0
3 years ago
Which equation is equivalent to n + 4 = 11? *
dangina [55]

Answer:

(n + 4) *2 = 11 * 2

Step-by-step explanation:

(n + 4) *2 = 11 * 2

Divide both sides by 2

\frac{(n + 4) *2}{2} = \frac{11 * 2}{2}

n + 4 = 11

5 0
3 years ago
Plwees help:)
Klio2033 [76]
Answer #1- 8 mins
Answer #2-$0.571

Explanation for #1:

For this first equation you need to find 1 mike per ___ minutes. To get from 10 to 1, you need to divide by 10. This can also be put into this equation—

10x=80

So, to find how many minutes for each mile, divide 80 by 10. This will result in 8. This means that Dan ran 1 mile in 8 minutes.


Explanation for #2:

For this next one we see that we need to find how much Yoko spent on each pound of rice.

Since we are trying to find 1 pound of rice per ___ dollars, we need to divide both 14 and 8 by 14. This can also be put into this equation—

14x=8

Once this is done we know that 1 pound of rice is equal to 0.571428571428571 cents. But, since you are required to round to the nearest hundredth, the answer will only be $0.571.

Hope this helps comment below for more questions :)
7 0
3 years ago
Help solve 4 and 5 please
Sloan [31]

Answer:

Step-by-step explanation:

4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.

b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.

c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.

d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.

e). If a parallelogram has four congruent sides, then it must be a SQUARE.

5). Given quadrilateral SELF is a rhombus.

a). All sides of a rhombus are equal,

   Therefore, ES = EL = 25

b). Diagonals of a rhombus bisects the opposite angles,

   Therefore, m∠ELS = m∠FLS

    3x - 2 = 2x + 7

    3x - 2x = 7 + 2

    x = 9

c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.

m∠ELF = 2(m∠ELS) = 2(2y - 9)

m∠LES = 2(m∠LEF) = 2(3y + 9)

And 2(2y - 9) + 2(3y + 9) = 180

(2y - 9) + (3y + 9) = 90

5y = 90

y = 18  

6 0
3 years ago
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