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aivan3 [116]
3 years ago
5

The growth in population is calculated by birth rate minus death rate. This is called...

Geography
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:

rate of natural increase.

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Someone please answer question two for me
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Thank you hope this helps
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Using a pen, draw a line exactly along the contact (boundary) between the Vishnu Schist and the relatively horizontal sedimentar
Serga [27]

Answer: Hello some parts of your question is missing attached below is the missing detail

answer :

1) attached below

2) Non-conformity

Explanation:

1) Line along the boundary between Vishnu schist and relatively horizontal sedimentary rocks

attached below

2) The type of unconformity traced above is called Non - Conformity

i.e. when a sedimentary rock lies above an igneous rock or a metamorphic rock it is called Non-conformity

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What geographic feature allowed the Babylonian Empire to arise in Mesopotamia?
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Suppose 0 is an angle in the standard position whose terminal side is in Quadrant IV and cot0= -6/7 Find the exact values of the
Sergio039 [100]
<h2>\sin \theta=\dfrac{p}{h} =\dfrac{-7}{\sqrt{85} }, \cos \theta=\dfrac{b}{h} =\dfrac{6}{\sqrt{85}}, \tan \theta=\dfrac{p}{b} =\dfrac{-7}{6},</h2><h2>\sec \theta=\dfrac{h}{b} =\dfrac{\sqrt{85} }{6} and \csc \theta=\dfrac{h}{p} =\dfrac{-\sqrt{85}}{ 7}</h2>

Explanation:

Given,

\cot \theta= \dfrac{-6}{7}

To find, the exact values of the five remaining trigonometric functions of \theta = ?

We know that,

\cot \theta= \dfrac{-6}{7}=\dfrac{b}{p}

Where, b = base and p = perpendicular

By Pythagoras's theorem,

Hypotaneous, h=\sqrt{p^2+b^2}

=\sqrt{(-6)^2+7^2}=\sqrt{36+49} =\sqrt{85}

In IVth quadrant,

\cot \theta and \sec \theta are positive.

\sin \theta=\dfrac{p}{h} =\dfrac{-7}{\sqrt{85} }, \cos \theta=\dfrac{b}{h} =\dfrac{6}{\sqrt{85}}, \tan \theta=\dfrac{p}{b} =\dfrac{-7}{6},

\sec \theta=\dfrac{h}{b} =\dfrac{\sqrt{85} }{6} and \csc \theta=\dfrac{h}{p} =\dfrac{-\sqrt{85}}{ 7}

7 0
3 years ago
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