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3 years ago

Convert 653 in base 7 to base 10

1 answer:

3 0

Converting 653 to base 10.
6*102=600
5*101=50
3*100=3
Adding all to get Ans=65310

Step2 converting 65310 to 7

The equation calculation formula for 65310 number to 7 is like this below.
7|653
7|93|2
7|13|2
7|1|6
7|1|1
Ans:16227

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Two Pairs Of Jeans Cost $75 before tax. If the total paid for the two pairs of jeans with tax was $81, what is the percentage of

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Answer:

31%

Step-by-step explanation:

100- 75 = 25

25/81 = 0.308 = 31%

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4 years ago

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An image point has coordinates B'(5, -6). Find the coordinates of its pre-image if the translation used was (x - 4, y + 5).

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Here, Translation factor: (x, y) → (x-4, y+5)

Coordinates of Image = B'(5, -6)

So, x-coordinate of point = x-4 = 5, x = 9
y-coordinate of point = y+5 = -6, y = -11

In short, Your Answer would be: Option B) (9, -11)

Hope this helps!

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4 years ago

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Solve 1/f=1/a+1/b for f

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Answer:

f=ab/a+b

Step-by-step explanation:

Let's solve for f.

1/f=1/a+1/b

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3 years ago

Which scientist developed the first model of the atom that showed the structure of the inside of an atom?

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Answer: O Thomson

Step-by-step explanation:

The first model which is known as "Thomson atomic model" of the atom that showed the structure of the inside of an atom is developed by William Thomson. The model gave description of an inner structure of the atom theoretically.
His theory was supported by J J Thomson who had discovered electron.
He discovered negatively charged particle during a cathode ray tube experiment

So, the correct option is "Thomson" .

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A shoe manufacturer was investigating the weights of men's soccer cleats. He felt that the weight of these cleats was less than

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Answer:

The conclusion is that the researcher was correct

Step-by-step explanation:

From the question we are told that

The sample size is $n = 13$

The sample mean is $\= x = 9.63$

The standard deviation is $s = 0.585$

The significance level is $\alpha = 0.05$

The Null Hypothesis is $H_o : \mu = 0$

The Alternative Hypothesis is $H_a = \mu < 10$

The test statistic is mathematically represented as

$t = \frac{\= x - \mu }{\frac{s}{\sqrt{n} } }$

Substituting values

$t = \frac{9.63 - 10 }{\frac{0.585}{\sqrt{13} } }$

$t = - 2.280$

Now the critical value for $\alpha$ is

$t_{\alpha } = 1.645$

This obtained from the critical value table

So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected

The conclusion is that the researcher was correct

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4 years ago