Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
Answer:
D. Yes, because the scale does not start at 0.
Step-by-step explanation:
Answer: -9°F
Step-by-step explanation:
From the question, we are told that the temperature at 6:00 am was -12 Fahrenheit and that the temperature increased by 1/2 Fahrenheit each hour for 6 hours.
The temperature, in degrees Fahrenheit, at noon would be:
= -12°F + 1/2(6)
= -12°F + 3°F
= -9°F
Answer:
D
Step-by-step explanation:
Then you find the intersection and get the bisector without a protractor :)
Answer:
<u><em>There is not enough information to know if there is a statistically significant difference in the number of children per family between the three countries.</em></u>
Step-by-step explanation:
There are other important information that are necessary in order to reach a decisive conclusion. This includes not just the f value only, but the alpha value, f critical value and the p-value after conducting the one way ANOVA.
Since we do not have information about the p value, as well as the alpha value there is no way to compare the effects of all the variables.
Therefore, no decision can be made by the Pediatrician without knowing what the p value is and the apha value is.
