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3 years ago

. Classify ABC if the vertices are A(-12,5), B(12,5), and C(10, 17).

Mathematics

2 answers:

timurjin [86]3 years ago

3 0

Answer:

acute scalene

Step-by-step explanation:

iogann1982 [59]3 years ago

3 0

C-Acute scalene is the right answer I think

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Elisa is nearing graduation. She just met with her counselor and he showed her this information.

Arada [10]

Answer: $14,000

Step-by-step explanation:

Given the following :

Room & Board = $11,500

Work - study = $8000

Grant & scholarship = $9500

Tuition fee = $9500

If she pays balance with a student loan, how much will she need to borrow:

Elisha's bill:

Tuition fee and room and board

($9500 + $11500) = $21,000

Elisha's earning:

Work - study and scholarship & grant

($8000 + $9500) = $17500

Therefore,

Amount to borrow per year :

$21,000 - $17,500 = $3500

For four years :

4 × $3,500 = $14,000

8 0

3 years ago

christina and her 2 friends spent $25.02 at there favorite restaraunt . if they split the cost equally how much will they each p

ad-work [718]

Answer:

$8.34

Step-by-step explanation:

Simply divide $25.02 by three, since three people are splitting the cost.

8 0

2 years ago

Chipper had 189 hits in 572 at bats calculate chippers batting average for season by dividing the number if hits by the number o

lord [1]

Answer:

0.330

Step-by-step explanation:

Divide the number of hits (189) by the number of bats (572)

189/572=0.330

8 0

3 years ago

Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

5 0

3 years ago

Can someone help me?It's urgent and thank you!

torisob [31]

Answer:

x = 4 is the answer

PLease give a brainliest

3 0

2 years ago