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wariber [46]
3 years ago
15

The expression 1.08 + 1.02b predicts the end- of the year value if a financial portfolio where S is the value of the stocks and

B is the value of bonds in the portfolio at the beginning of the year
What is the predicted end-of value of a portfolio that begins the year with $200 in stocks and $100 in bonds?
Mathematics
1 answer:
iragen [17]3 years ago
4 0

Answer:

We have

Stock = $200

Bonds = $100

Substitute these values into 1.08s+1.02b, where 's' is stock and 'b' is bond

.() + .() =

Predicted end of year value is $318

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Need help again .........
xenn [34]

Answer:

(:

Step-by-step explanation:

3 0
3 years ago
Given here are a set of sample data: 12.0, 18.3, 29.6, 14.3, and 27.8. the sample standard deviation for this data is equal to _
disa [49]
The answer is 7.9306

Using the formula in the attached:
Where: xi = sample value; μ = sample mean; n = sample size

1.) Calculate the mean first:
μ = 12.0 + 18.3 + 29.6 + 14.3 + 27.8 / 5
   = 102 / 5
μ = 20.4

2.) Using the mean, calculate (xi - μ)² for each value:
(12.0 - 20.4)² = 70.56
(18.3 - 20.4)² = 4.41
(29.6 - 20.4)² = 84.64
(14.3 - 20.4)² = 37.21
(27.8 - 20.4)² = 54.76

3.) Sum the squared differences and divide by n - 1.
μ = 70.56 + 4.41 + 84.64 + 37.21 + 54.76
   = 251.58 / 5-1
μ = 62.895 (this is now called sample variance)

4.) Get the square root of the sample variance:
 √62.895 = 7.9306

3 0
3 years ago
Please help, and please give me an explanation.
vichka [17]
I Believe that it is not the last 3 Answers.
7 0
3 years ago
How do I find this? Please help.
erma4kov [3.2K]
Use pie and know your diameter or you can use your radius
8 0
2 years ago
Read 2 more answers
A parking lot is 20 feet long. One tortoise starts at the edge of the parking lot and moves at a rate of 6 feet per minute. Anot
anygoal [31]

Answer:

Kindly check explanation

Step-by-step explanation:

Length of parking lot = 20 feets

Speed of tortoise which starts at the edge = 6 feets per minute

Speed of tortoise which starts 4 feets from the edge = 2 feets per minute

Equation to represent when they will be in the same spot.

Distance = speed * time

Distance of Tortoise at edge = 6ft/min * t = 6t - - (1)

Distance of the other tortoise = (4 + 2t) - - - (2)

Equating both (1) and (2)

6t = 4 + 2t

6t - 2t = 4

4t = 4

t = 4/4

t = 1

Hence, they'll be at the same spot after 1 minute.

6 0
3 years ago
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