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2 years ago

Y = 2x x = -y + 6 The solution is ( ? , ? )

Mathematics

1 answer:

Keith_Richards [23]2 years ago

5 0

Answer:

18,14

Step-by-step explanation:

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Which interval for the graphed function has a local minimum of 0?

koban [17]

Answer:

{2,4} I know cause I JUST took the same test yesterday :) I guess I didin't help much huh

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2 years ago

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For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm

Paraphin [41]

The ratio of the area of the first figure to the area of the second figure is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the first figure to the area of the second figure

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of two similar polygons is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

$(\frac{14 \ mm}{7 \ mm})^{2}$

$= \frac{196 \ mm^{2} }{49\ mm^{2} }$

$=\frac{4}{1}$

= 4:1

Hence, the ratio of the area of the first figure to the area of the second figure is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

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1 year ago

Round to the nearest whole. 782.36

ratelena [41]

The answer would be 782 because you would round down.

6 0

2 years ago

Read 2 more answers

A fisherman separated of his catch into 2 equal bins.

ohaa [14]

This question doesn't make any sense please reword and i will do my best to solve.

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2 years ago

(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.

Andreyy89

$\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1$

Recall that

$\displaystyle\sum_{i=1}^n1=n$

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

Your sums start at $i=3$ , so in order to apply these formulas directly, you need to compensate for the missing first two terms:

$\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8$

$\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52$

$\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}$

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2 years ago