From what I got there is one real solution :)
Rearrange the second equation to give y=2-2x, substitute into the first equation to give you a value for x and then using that you can work out y for the exact coordinates of intersection :)
Also they are both straight line graphs so they will either have one or no solutions
Hope this helped :)
Answer:
350
Step-by-step explanation:
Introduction. Percent, p%
'Percent (%)' means 'out of one hundred':
p% = p 'out of one hundred',
p% is read p 'percent',
p% = p/100 = p ÷ 100
120% = 120/100 = 120 ÷ 100 = 1.2
100% = 100/100 = 100 ÷ 100 = 1
Percentage of 120% of what number = 420?
120% × ? = 420
? =
420 ÷ 120% =
420 ÷ (120 ÷ 100) =
(100 × 420) ÷ 120 =
42,000 ÷ 120 =
350
<h2>Proof</h2><h3>How do we check the result?</h3>
If 120% × 350 = 420 =>
Divide 420 by 350...
... And see if we get as a result: 120%
<h3>Note:</h3>
Multiply a number by the fraction 100/100,
... and its value doesn't change.
100/100 = 100 ÷ 100 = 1
n/100 = n%, any number.
<h2>Hope it is helpful....</h2>
Answer:
A and B are correct, but A is most correct.
Step-by-step explanation:
just do Pythagorean theorem and see which numbers add up to each other. if you do them for all 4 answers, you see d and c do not equal to each other. b is almost correct, and a comes out exact.
<h3>E
xplanation:</h3>
Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).
cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)
(1 -sin^2(θ))cot^2(θ) = . . . . . replace cos^2 with 1-sin^2
cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin
cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired
Answer: ∠ J = 62° , ∠ K = 59° , ∠ L = 59°
<u>Step-by-step explanation:</u>
It is given that it is an Isosceles Triangle, where L J ≅ K J
It follows that ∠ K ≅ ∠ L
⇒ 5x + 24 = 4x + 31
⇒ x + 24 = 31
⇒ x = 7
Input the x-value into either equation to solve for ∠ K & ∠ L:
∠ K = 5x + 24
= 5(7) + 24
= 35 + 24
= 59
∠ K ≅ ∠ L ⇒ ∠ L = 59
Next, find the value of ∠ J:
∠ J + ∠ K + ∠ L = 180 Triangle Sum Theorem
∠ J + 59 + 59 = 180
∠ J + 118 = 180
∠ J = 62
