Answer:
The work will be "1909212.015 J". The further explanation is given below.
Step-by-step explanation:
The given values are:
Liquid's density
= 760 kg/m³
Height
= 3 meters
Gravity
g = 3.8 m/s²
Value of y is:
y = 5 log (x-2)
y = 0
y = 4
As we know,
⇒ ![\Delta V=\pi r^2 \Delta y](https://tex.z-dn.net/?f=%5CDelta%20V%3D%5Cpi%20r%5E2%20%5CDelta%20y)
⇒ ![y =5log(x-2)](https://tex.z-dn.net/?f=y%20%3D5log%28x-2%29)
⇒ ![\frac{y}{5} =log (x-2)](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B5%7D%20%3Dlog%20%28x-2%29)
⇒ ![e^{\frac{y}{5}}=(x-2)](https://tex.z-dn.net/?f=e%5E%7B%5Cfrac%7By%7D%7B5%7D%7D%3D%28x-2%29)
⇒ ![x=e^{\frac{y}{5}}+2](https://tex.z-dn.net/?f=x%3De%5E%7B%5Cfrac%7By%7D%7B5%7D%7D%2B2)
Now,
![\Delta F=ma](https://tex.z-dn.net/?f=%5CDelta%20F%3Dma)
![=760 \pi (e^{\frac{y}{5}}+2)^2(9.8)\Delta y](https://tex.z-dn.net/?f=%3D760%20%5Cpi%20%28e%5E%7B%5Cfrac%7By%7D%7B5%7D%7D%2B2%29%5E2%289.8%29%5CDelta%20y)
So that,
⇒ ![\Delta W = \Delta F.distance](https://tex.z-dn.net/?f=%5CDelta%20W%20%3D%20%5CDelta%20F.distance)
![=\Delta F(4-y)](https://tex.z-dn.net/?f=%3D%5CDelta%20F%284-y%29)
The required work will be:
⇒ ![W=760\times 9.8 \pi \int_{3}^{0}(e^{\frac{y}{5}}+2)^2 (\Delta-y)dy](https://tex.z-dn.net/?f=W%3D760%5Ctimes%209.8%20%5Cpi%20%5Cint_%7B3%7D%5E%7B0%7D%28e%5E%7B%5Cfrac%7By%7D%7B5%7D%7D%2B2%29%5E2%20%28%5CDelta-y%29dy)
![=760\times 9.8 \pi[{-20(y-9)^{e^{\frac{y}{5}}}-2(y-8)y}]](https://tex.z-dn.net/?f=%3D760%5Ctimes%209.8%20%5Cpi%5B%7B-20%28y-9%29%5E%7Be%5E%7B%5Cfrac%7By%7D%7B5%7D%7D%7D-2%28y-8%29y%7D%5D)
![=760\times 9.8 \pi[81.455]](https://tex.z-dn.net/?f=%3D760%5Ctimes%209.8%20%5Cpi%5B81.455%5D)
![=1909212.015 \ J](https://tex.z-dn.net/?f=%3D1909212.015%20%5C%20J)
PLEASE include a picture so we can answer!!!
I don't know what you're asking. Is the question asking for the area, or perimeter of the store? for perimeter, the answer is 162 meters, and for area the answer is 1638
Answer:
1*(9+7):(2+6)*1=2
Step-by-step explanation:
B is the answer fam because I did this before and b was the answer